AUTOSAR C++14 Rule A8-4-12
A std::unique_ptr shall be passed to a function as: (1) a copy to express the function assumes ownership (2) an lvalue reference to express that the function replaces the managed object.
Since R2022b
Description
Rule Definition
A std::unique_ptr shall be passed to a function as: (1) a copy to express the function assumes ownership (2) an lvalue reference to express that the function replaces the managed object.
Rationale
 You use an std::unique_ptr smart pointer to indicate that only one
        smart pointer owns the managed object. A smart pointer manages the lifetime of a dynamically
        allocated object and destroys that object when the smart pointer goes out of scope. Pass an
          std::unique_ptr smart pointer to a function in one of these ways:
- If you expect the function to take ownership of the managed object, pass the smart pointer by value. For instance, the - std::unique_ptrargument of the caller in this code is moved-from and ownership of the- intobject is transferred to an implicitly constructed- std::unique_ptrsmart pointer, which is then passed to the function- func().- void func(std::unique_ptr<int>) {} void otherFunc() { auto smartPtr = make_unique<int>(1); func(std::move(smartPtr)); //caller }
- If you expect the function to replace the object that the smart pointer manages, pass the smart pointer as an lvalue reference. For instance, you might replace the managed object by calling the assignment operator or the - reset()smart pointer member function. For example,- uniquePtris reset inside- func()and no longer manages the- intobject in this code.If you do not intend to replace the managed object, pass an lvalue reference to the managed object itself.- void func(std::unique_ptr<int>& smartPtr) { smartPtr.reset(); } void otherFunc { auto uniquePtr = make_unique<int>(1); func(std::move(uniquePtr); //caller }
You cannot move or reset a const-qualified lvalue
        reference to an std::unique_ptr smart pointer. If you do not intend to
        modify the managed object, pass a const-qualified lvalue reference to the
        managed object instead.
There is no violation of this rule if you pass an rvalue reference to an
          std::unique_ptr smart pointer and the reference is moved into a
        different std::unique_ptr smart pointer inside the function. For
        instance, rvalueRefPtr is passed by rvalue reference to an
          std::unique_ptr smart pointer and then moved into a different smart
        pointer std::unique_ptr
        newPtr.
void func(std::unique_ptr<int>&& rvalueRefPtr)
{
    std::unique_ptr<int> newPtr(std::move(rvalueRefPtr));
}Polyspace Implementation
Polyspace® the use of a parameter passed as an lvalue reference to
          std::unique_ptr if that parameter is not reset.
Polyspace considers the parameter reset in these cases:
- The parameter is used as the destination of a move assignment. 
- The parameter is moved-from through a call to - std::move.
- The parameter is used as the argument of - std::unique_ptrmember functions- reset(),- swap(), or- release().
- The parameter is used as the argument of any function that takes a non- - constqualified lvalue reference to an- std::unique_ptrsmart pointer, regardless of the implementation of the callee.
Polyspace also reports the use of const-qualified lvalue references
        to an std::unique_ptr smart pointer because you cannot modify the pointer
        and transfer ownership of the managed object.
Polyspace does not report the use of smart pointers as parameter types in these cases:
- The pointer is used as a parameter of a template function. The parameter type of template functions depends on the instantiation of the function and a fix is not always possible at the template design level. For instance, Polyspace does not report the use of unique pointer - ptras parameter in this code.- #include <iostream> #include <memory> #include <cassert> template <typename T> double XtimesY(T& ptr) // Use of ptr not flagged { return (ptr->x) * (ptr->y); // ... } struct S { double x; double y; S(double x0, double y0) : x{x0}, y{y0} {} }; void func() { auto a = std::make_unique<S>{100.0, 200.0}; auto b = new S(100.0, 200.0); assert(XtimesY(a) == XtimesY(b)); }
- The smart pointer parameter is captured by a lambda function inside the function body. For instance, Polyspace does not report a violation when you use an lvalue reference to unique pointer - ptras a parameter of- func()because it is captured by a lambda function inside the body of- func(). Polyspace reports the use of lambda function parameter- up1because its lifetime is not modified inside the lambda function.- #include <memory> struct S { double x; double y; S(double x0, double y0) : x{x0}, y{y0} {} }; void func(std::unique_ptr<S>& ptr) { // no defect is detected on 'ptr' auto lambdaF = [&ptr0 = ptr] // 'ptr' is captured (by reference) (std::unique_ptr<S> up1) // Non-compliant { // lifetime of 'up1' not affected // ... }; auto b = std::make_unique<S>(100.0, 200.0); lambdaF(std::move(b)); }
Troubleshooting
If you expect a rule violation but Polyspace does not report it, see Diagnose Why Coding Standard Violations Do Not Appear as Expected.
Examples
Check Information
| Group: Declarators | 
| Category: Required, Automated | 
Version History
Introduced in R2022b