Vary the duty of PWM signal using pause

There are two switches in the system. Normally switch 1 is ON. But when there is a sudden change in the input, the duty of the second switch should be varied proportional to the change. I am using pause() function to vary the ON time of second switch. Below is the code which I have done.

But the problem I am facing is the ON time is the same irrespective of change in input. Is there something wrong in the written logic?

function [PWMA ,PWMB,Test]= fcn(u)

PWMA=0;

PWMB=0;

%td=0;

Test =1;% Test variable for debugging

persistent td;

if isempty(td)

td = 0;

end

persistent throttleNew; % static variable to identify change in input

if isempty(uNew)

uNew = 0;

end

t_info();

function t_info()

uOld=uNew; %throttleOld variable to identify the previous position

uNew=u;

if ((uOld==0)&&(uNew==0))

PWMA=0; %Pulses tothe 1st switch

PWMB=0; %Pulses tothe 2nd switch

Test =2;

elseif((uOld~=uNew)&& (uOld < uNew)) %identify any change in input and if change happens

td=(uNew-uOld)*10;

disp(td)

% tic

% while(td>0)

%if(toc>=td)

%for i=0:0.0001:td

PWMA=0 ; %Switch the 2n

PWMB=1;

pause(td); % determines the duration for which 2nd switch is on

Test =3;

% end

%end

% td=(uNew-uOld)*10

else

% pause((uNew-uOld)*10)

PWMA = 1;

PWMB=0;

Test =4;

end

end

end

Answer 1

[VBBV]

     t_info(u);
      function t_info(u) 

Pass the input variable to the function call t_info

[Chirag Goyal]

Hi,

But this still wont change the duty of the second switch. The second switch is on for 0.001 seconds only always, even for smaller changes in input as well as a large change.

[VBBV]

It seems total cycle time is not mentioned in your code. How is it possible to determine the duty cycle time in seconds for second switch when it's triggered on ?

[VBBV]

You must divide the time duration of ON state of 2 switch with its total cycle time.

[Chirag Goyal]

Second switch should be ON for (uNew-uOld)*10 seconds. How to do this ?

[Chirag Goyal]

According to my code, I am using pause (uNew-uOld)*10 ) after making PWM=1