能不能把下面储存在元​胞里面的t(i)换成​具体的值,是不是有强​制计算什么的

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玉成
玉成 on 28 Jun 2022
Commented: 玉成 on 29 Jun 2022
代码:
clear
clc
t=[1 2 3 4 5]
for i=1:4
F{i}=@(a)t(i+1).^a-t(i).^a
end
结果:
F =
1×4 cell 数组
{@(a)t(i+1).^a-t(i).^a} {@(a)t(i+1).^a-t(i).^a} {@(a)t(i+1).^a-t(i).^a} {@(a)t(i+1).^a-t(i).^a}
  1 Comment
Walter Roberson
Walter Roberson on 29 Jun 2022
Approximate translation:
Can you replace the t(i) stored in the cell below with a specific value? Is there any mandatory calculation?

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Accepted Answer

Walter Roberson
Walter Roberson on 29 Jun 2022
t=[1 2 3 4 5]
t = 1×5
1 2 3 4 5
for i=1:4
cmd = sprintf('@(a)%.16g.^a-%.16g.^a', t(i+1), t(i));
F{i} = str2func(cmd);
end
F
F = 1×4 cell array
{@(a)2.^a-1.^a} {@(a)3.^a-2.^a} {@(a)4.^a-3.^a} {@(a)5.^a-4.^a}
  1 Comment
玉成
玉成 on 29 Jun 2022
谢谢

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