How to count number of ones and zeros in a binary number?

I am having some set of binary numbers. I need to count the number of ones and zeros in each binary number. If a binary number has even number of ones then the output has to be '1' or it has to be '0'. Thank you in advance.
Example:
A=1100
B=0100
output of A =1
output of B = 0

 Accepted Answer

I will assume that your binary numbers are stored as a character array, which is how Matlab normally works, e.g.
A = dec2bin(20)
A = '10100'
B = dec2bin(21)
B = '10101'
Now in the example above, A has an even and B has an odd number of ones respectively.
your desired output can be easily obtained with
1-mod(nnz(A=='1'),2)
ans = 1
1-mod(nnz(B=='1'),2)
ans = 0

3 Comments

Thank you for the reply. Actually i am having an array of 15 binary numbers and i need to apply the above mentioned concept to each numbers.
Example:
A=[ 1110, 0111, 0110, 1111]
Expected output:
B= 0, 0, 1, 1
A= [1110, 0111, 0110, 1111];
B = 1-mod(sum(num2str(A') == '1',2),2)
B = 4×1
0 0 1 1
Thank you for the reply. This is what i needed.

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More Answers (1)

% if you use char to represent binary numbers
A='1100';
mod(sum(A=='1'), 2) == 0
ans = logical
1
% if you use double to represent binaray numbers, you can do the conversion
% first
A = 1100;
A = num2str(A)
A = '1100'
mod(sum(A=='1'), 2) == 0
ans = logical
1

4 Comments

Not sure you can convert from double to binary (char array) for any given number.
A = 0100;
A = num2str(A)
A = '100'
Or am I missing something?
To count number of 1, it is perfectly fine.
If you do need to get 0100, you have to specify the number of digits and leading 0s using sprintf:
A = 0100;
A = sprintf('%04d', A)
A = '0100'
Thank you for the reply. Actually i am having an array of 15 binary numbers and i need to apply the above mentioned concept to each numbers.
Example:
A=[ 1110, 0111, 0110, 1111]
Expected output:
B= 0, 0, 1, 1

Sign in to comment.

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