Generate ones and zeros based on size of each element in a matrix nxn

i have a matrix a= [3 4 6; 0 2 3; 4 5 6] and i want to create a new matrix with ones and zeros like this:

one_zero= [ 1 1 1 0 0 0 0 1 1 1 1 1 1; 1 0 0 1 1 1; 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1]

in order to match the gaps for the one_zero matrix to have nxn columns, i want to fill gaps with 0 ( when for example the sum of first row does not match with the sum of the second row)

How it can be done?

Answer 1

[Dyuman Joshi]

The output corresponding to 0 in a (i.e. a(2,1)) is a single 1. If that is the desired output, you will have to replace all the zeros in the matrix with one.

a = [3 4 6; 0 2 3; 4 5 6];
a(a==0)=1;
%sum of each row
m = sum(a,2);
s = size(a);
%preallocating the output matrix
out = zeros(s(1),max(m));
%vector for repetition
vec=rem(1:s(2),2);
for k=1:s(1)
    out(k,1:m(k))=repelem(vec,a(k,:));
end
out

out = 3×15

1 1 1 0 0 0 0 1 1 1 1 1 1 0 0 1 0 0 1 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1

[Andreas Aristotelous]

Thank you very much @Dyuman Joshi. Suppose i wanted to have a specific number of columns for the out matrix (i.e columns=100) and the max sum of rows is for example 78 how can i change the code? The remaining 22 columns should contain 0 .

[Dyuman Joshi]

If you have a predefined value for number of columns, you can use it directly.

But note that the value has to be equal to or greater than the max value of sum of rows.

a = [3 4 6; 0 2 3; 4 5 6];
a(a==0)=1;
%sum of each row
m = sum(a,2);
s = size(a);
%let the pre-defined value be 20
pval=20;
%preallocating the output matrix according to pre-defined value
out = zeros(s(1),pval);
%vector for repetition
vec = rem(1:s(2),2);
for k = 1:s(1)
    out(k,1:m(k))=repelem(vec,a(k,:));
end
out

out = 3×20

1 1 1 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 1 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 1 1 1 1 1 1 0 0 0 0 0

[Andreas Aristotelous]

Thank you again @Dyuman Joshi. I really appreciate your help !