need help with " Error using vertcat Dimensions of matrices being concatenated are not consistent"
671 views (last 30 days)
Show older comments
Can anybody help me, cant understand why do i get this error when i run it?
i have attached my code.
thanks
3 Comments
Abhilash
on 6 Dec 2022
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
Z = table ([5:6;5],['M','F','M'],'VariableName',{'age','gender'},'RowName',{'A','B','C'})
Stephen23
on 6 Dec 2022
"Dimensions of arrays being concatenated are not consistent."
[5:6;5]
^^^ 1x2, i.e. 1 row 2 columns
^ 1x1, i.e. 1 row 1 column
How do you expect to vertically concatenate arrays with different numbers of columns?
Also note that square brackets are a contcatenation operator, so your code
['M','F','M']
concatenates three scalar characters into one character vector, and is exactly equivalent to:
'MFM'
You probably intended to define a string column vector:
["M";"F";"M"]
Answers (5)
Thorsten
on 18 May 2015
When you vertically connect matrices using ; the matrices must have the same number of columns.
A = ones(10, 3);
B = zeros(20, 4);
C = [A; B]
You get
Error using vertcat
CAT arguments dimensions are not consistent.
Instead you can write
B = zeros(20, 3);
C = [A; B]; % works, A and B have same number of rows
5 Comments
Jan
on 19 May 2015
Edited: Jan
on 19 May 2015
I guess that this fails:
t = 0:0.1:10;
...
Qin_doot = [4; 2*t; 10];
the sizes of the scalars 4 and 10 do not match with the size of t.
The description as text "ive get a 3X1 vector by multiplying ..." is less useful than posting the line of code you are talking of.
3 Comments
John Amakali
on 9 May 2018
Edited: Walter Roberson
on 9 May 2018
hi guys , i have the same problem... i have attached my code. someone help please.
Warning: Unsuccessful read: A timeout occurred before the Terminator was reached..
Error using vertcat
Dimensions of matrices being concatenated are not consistent.
Error in GUI>pushbutton1_Callback (line 144)
set(M,'Zdata',[Tdata; zeroIndex],'Cdata',[Tdata; Tdata]);
Error in gui_mainfcn (line 95)
feval(varargin{:});
Walter Roberson
on 9 May 2018
We do not know what size(Tdata) is or size(zeroIndex) .
The message about timeout suggests that you might be doing a serial read or read from arduino or raspberry, and that it is not returning as much data as you expect. If your Tdata is the actual received data and zeroIndex is built under the assumption that all of the requested data was received, then they could easily end up with incompatible sizes.
A N
on 10 Feb 2018
Edited: Stephen23
on 10 Feb 2018
I've got another problem with using vertcat Dimensions of matrices being concatenated are not consistent.
I'm trying to write a code to make a transmission characteristic of the Gaussian filter from this
My code is:
lambdac=0.8; %mm
dx=0.001; %mm
alpha=sqrt(log(2)/pi);
disp(alpha);
x=(-lambdac:dx:lambdac);
S=(1/alpha*lambdac).*exp(-pi*(x/alpha*lambdac).^2);
S=S/sum(S);
figure(1)
plot(x,S)
xlabel('Odległość [mm]')
ylabel('Wzmocnienie')
xlim([-1 1])
%Przykład 5.2
m=size(S,1); %długość filtru gaussowskiego
l=8; %długość punktów pomiarowych na profilu
n=1/dx; %liczba punktów pomiarowych na profilu
S=[zeros(n/2-floor(m/2),1); S; zeros(n/ 2-floor(m/2)-1,1)]; %copied from %previous link
Sf=fft(S); %transformata Fouriera S
j=(2:1:floor (n/2)+1); %generuje falę o długości dla danych X
wave=n*dx./(j-1);
figure (2)
semilogx (wave, 100*abs(Sf(2:floor (n/2)+1,1)));
xlabel('Długość fali [mm]')
ylabel('Amplituda [%]')
hold off
I've tried also with
S=[zeros(n/2-floor(m/2)-1,1); S; zeros(n/ 2-floor(m/2)+1,1)];
but no result. After n=1/dx I've found:
a=zeros(n/2-floor(m/2),1);
size(a);
disp(size(a));
S;
size(S);
disp(size(S));
c=zeros(n/2-floor(m/2)+1,1);
size(c);
disp(size(c));
and result:
500 1
1 1601
501 1
Any idea how to solve it?
1 Comment
Stephen23
on 10 Feb 2018
Edited: Stephen23
on 10 Feb 2018
So S has 1601 columns and you are trying to vertically concatenate it with two arrays, each of which has just one column. You need to ensure that the number of columns or rows is the same, e.g.:
R = n/2-floor(m/2);
S = [zeros(1,R-1), S, zeros(1,R+1)];
A N
on 10 Feb 2018
Edited: Walter Roberson
on 10 Feb 2018
Great! Works!
After it I would like to do a FFT of S, but
My code:
Sf=fft(S); %transformata Fouriera
j=(2:1:floor(n/2)+1); %faa o danej długości
size(j);
disp(size(j));
wave=n*dx./(j-1);
size(wave);
disp(size(wave));
figure(2)
semilogx(wave,100*abs(Sf(2:floor(n/2)+1,1)))
xlabel('Długość fali [mm]')
ylabel('Amplituda [%]')
Command Windows shows as a result of those displays:
1 500
1 500
Index exceeds matrix dimensions.
Error in proba (line 61)
semilogx(wave,100*abs(Sf(2:floor(n/2)+1,1)));
Error in proba (line 65)
semilogx(wave,100*abs (2:floor(n/2)));"
Do you know how to solve it? Maybe my error is easy but I've been doing only spectral FFTs and would like to know more about examples like this (no Fs and spectral). In Help I found only spectral FFT. Line with semilog I copied from this book, and really hard to find out - is this wrong?
Edit:
Writing:
semilogx(wave,100*abs(Sf(2:floor(n/2)+1)));
impacts of this plot:
7 Comments
MANYINGA MARC
on 24 Mar 2023
Bonjour la communauté. J'ai un code de calcul, Dan lequel je voudrais faire varier les éléments d'une matrice À, en fonction d'une variable temps t. Par exemple
t=0:10:60 A=[1 2*t 3 3*t 5 8 5 6 3] Affiche error using vertcat Besoin d'aide
1 Comment
Walter Roberson
on 24 Mar 2023
A=[1 2*t 3 3*t 5 8 5 6 3] would be an error if t is not a row vector.
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!