Save New Variable to the Workspace for every iteration with a 'for' cycle

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Hello all,
I've been trying to save the Q_bar(3x3 matrix) answer seperately for every theta input but I am failing to save the Q_bar answer for each iteration. Because the only output is the final Q_bar matrix.
for theta = [0,45,60,45,45,60,45,0];
m = cos(theta*pi/180);
n = sin(theta*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
Q_bar = Q_bar(theta);
end
The final output should be Q_bar(0) = [3x3 matrix] , Q_bar(45) = [3x3 matrix], Q_bar(60) = [3x3 matrix] etc.
What can I do?
Thank You already
  3 Comments
kerozi
kerozi on 23 May 2016
I have thought with another for loop inside should give an answer but it does not.
theta = [0,45,60,45,45,60,45,0];
for i=1:8;
m = cos(theta(i)*pi/180);
n = sin(theta(i)*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
Q_bar = Q_bar(theta(i));
end
AND I FORGOT TO TELL THAT Q MATRIX IS ALSO 3x3 MATRIX.

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Accepted Answer

Stephen23
Stephen23 on 23 May 2016
Edited: Stephen23 on 23 May 2016
Exactly as Adam said in their comment, just use a 3D array like this:
Q = randi(9,3,3);
vec = [0,45,60,45,45,60,45,0];
out = NaN([size(Q),numel(vec)]);
for k = 1:numel(vec)
theta = vec(k);
m = cos(theta*pi/180);
n = sin(theta*pi/180);
T = [m.^2 n.^2 2*m*n ; n.^2 m.^2 -2*m*n ; -m*n m*n m.^2-n.^2];
Tinv = inv(T);
Q_bar = Tinv*Q*T;
out(:,:,k) = Q_bar;
%Q_bar = Q_bar(theta);
end
But note that you should use \ instead of inv.
  1 Comment
kerozi
kerozi on 24 May 2016
Thank You, as much as it seems an easy task, it was hard for me to comprehend the overall. But you made it happen. Thank You so much.

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More Answers (1)

Steven Lord
Steven Lord on 23 May 2016
You're trying to create variables like Q_bar0, Q_bar45. etc.? DON'T DO THAT. That would make your code more difficult to read and probably slower. Read this Answer for an explanation.
Adam's suggestion is the recommended approach.
theta = 0:45:360;
M = zeros(3, 3, length(theta));
for k = 1:length(theta)
T = theta(k);
M(:, :, k) = [1 0 0; 0 cosd(T) -sind(T); 0 sind(T) cosd(T)];
end
The rotation matrix for the angle theta(N) [for N between 1 and length(theta)] is M(:, :, N).
And don't use inv, use the backslash operator \ instead.

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