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str2double conversion...

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Aniya
Aniya on 25 Oct 2016
Edited: Aniya on 11 Nov 2016
clc;
fid = fopen('fileName','r');
allText = textscan(fid,'%s','delimiter','\n')
allText = strfind(allText{1}, 'Num_X=');
strv =(find(~cellfun('isempty', allText)));% find position of Num_X
str = cell (11,1);
fseek(fid,0,-1);
for k = 1:11
str{k}= fgetl(fid);
end
W = str2double(str{strv});% trying to obtain number in that string.
Returns NaN .Why?

  2 Comments

Steven Lord
Steven Lord on 25 Oct 2016
Set a breakpoint on the last line of code then run your code. When you reach that last line, what is the value of this expression?
str{strv})
You're encountering this behavior listed in the documentation.
If str2double cannot convert text to a number, then it returns a NaN value.
It would be interesting / informative to see what you're trying to convert, knowing that we may be able to offer a suggestion as to how to resolve the issue.
Aniya
Aniya on 26 Oct 2016
I forgot to specify the position in a string...Thank you for your effort...

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Accepted Answer

dpb
dpb on 25 Oct 2016
Because str{strv} will be a single character and equal to 'N' assuming the string 'Num_X=' is in the text in the first line; otherwise it'll be whatever character happens to be in that position in the line. fgetl returns a character array; subscripting it with a single index returns only a single character, not a full string as does a reference to a cell string. Of course, str2double and friends aren't cellstring aware.
textscan is probably a better approach to reading the file; let's see a small subset of the file format...

  2 Comments

Aniya
Aniya on 26 Oct 2016
I need to specify the position in the particular string ....Ya ..I get it thank you so much for your support.
dpb
dpb on 26 Oct 2016
So show us the file...probably something like
...
l=fgetl(fid);
fscanf(l,'Num_X=%f')
or a variation thereon will directly parse the file format. Or, use textscan and can likely read the whole file or as many records as wanted without the loop and fgetl but no can help much w/o knowing what the file/record structure actually looks like.
Or, regular expressions can parse stuff, too, although I'm pretty much klewless on writing complex pattern-matching expressions therein...

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