I want to know find height and width of binary image and angle

Sample this image output Height 180 Width 145 and find degrees from center of picture 4 angle

Answer 1

[Guillaume]

Your question is really not clear, at a guess you want the height width and general angle of the white figure in your image. All can be simply obtained with regionprops.

But first of all, JPEG is completely the wrong format for storing binary images:

>>img = imread('bw00018.jpg');  %read image
>>intensities = unique(img(:))'  %get list of all intensity values in the image:
intensities = 
1×74 uint8 row vector

     0     1     2     3     4     5     6     7     8     9    10    11    12    13    14    15    16    17    18    19    20    21
    22    23    24    25    26    27    28    29    30    31    34    35    36    37    39   216   217   220   221   222   224   225
   226   227   228   229   230   231   232   233   234   235   236   237   238   239   240   241   242   243   244   245   246   247
   248   249   250   251   252   253   254   255

Your image is no longer binary due to the way standard jpeg compression works. Use a non-lossy image format such as PNG.

Anyway,

bw = img > 127;  %convert to binary image using arbitrary threshold
props = regionprops(bw, 'all');
shapeheight = props.BoundingBox(4)
shapewidth = props.BoundingBox(3)
shapeanglefromhorz = props.Orientation;

Orientation is the angle of the ellipse that best fit your shape.

[Adisorn Phanukthong]

I explain again this picture I want to find degree of picture 4 degree. first degree Top left. second degree top right. third degree bottom left. fourth degree bottom right. in white area

from center of picture

[Image Analyst]

This is not clear. What do you mean by degree? Degree is an angle, like 90 or 235 or other numbers between 0 and 360. A picture does not have a "degree" since it's just a rectangular list of numbers. You need to have at least 3 points to define an angle and thus a degree. Each of the "sectors" defined by your colored lines has an angle of 45 degrees. Is that what you're asking (probably not)?

[Adisorn Phanukthong]

yes that angle. red point from center

find top area in left and right,bottom left and right too.

[Image Analyst]

dx = xRed - xCentroid;
dy = yRed - yCentroid;
angle = atan2d(dy, dx);

[Adisorn Phanukthong]

I don't understand please detail more