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Matrix with binomial permutation

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Zheng Liu
Zheng Liu on 13 Feb 2017
Commented: Zheng Liu on 13 Feb 2017
I really had trouble finding the right words for the question. I'll try my best. Given a numerical number k (k>1), I want to get a [2^k, k] matrix with all possible binomial permutation. for K = 2, I hope to get: [1 1; 1 2; 2 1; 2 2]. for k = 3, the matrix will look like: [1 1 1; 1 1 2; 1 2 1; 1 2 2; 2 1 1; 2 1 2; 2 2 1; 2 2 2]. I could do for loop for each condition, like for k=3:
mat = [];
for digit1 = 1:2
for digit2 = 1:2
for digit3 = 1:2
mat(size(mat,1)+1,:) = [digit1 digit2 digit3];
end
end
end
But this is not generalized and efficient. Is there any thoughts on generating such matrix? Thanks!

Accepted Answer

Honglei Chen
Honglei Chen on 13 Feb 2017
dec2bin(0:2^K-1)-'0'+1
HTH
  1 Comment
Zheng Liu
Zheng Liu on 13 Feb 2017
That's why we like binary. Thanks!

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