Sort rows based on number of 1's in each row.

I have a matrix A = [1 1 0 1; 1 0 0 0 ; 1 0 1 0 ; 1 1 1 1]; I count the number of 1's in each row and I get count=[3 1 2 4]. I want to get A' = [1 1 1 1; 1 1 0 1; 1 0 1 0; 1 0 0 0]; How to get it. TIA.

Answer 1

[Stephen23]

>> A = [1,1,0,1;1,0,0,0;1,0,1,0;1,1,1,1];
>> [~,idx] = sort(sum(A,2),'descend');
>> A(idx,:)
ans =
   1   1   1   1
   1   1   0   1
   1   0   1   0
   1   0   0   0

[Ananya Malik]

Thanks a lot (y).