choose row cell of matrix

I have

 A=[1 2 0.1 0.2;...
    1 5 0.2 0.2;...
    2 3 0.4 0.4;...
    2 4 0.9 0.8;...
    2 5 0.3 0.4;...
    3 4 1.1 2.2]

and

B={[1,2,5],[3,4,6]} 

I want to get a C that rows of it, is B and column of it is all column of A

C=cell(1, size(B,2));
for i=1:length(B)
    for j=1:length(B{i})
    C{i}(j)=A(j,:)
    end
end

I want this result

C={[1 2 0.1 0.2 ;...
    1 5 0.2 0.2 ;...
    2 5 0.3 0.4],...
   [2 3 0.4 0.4 ;...
    2 4 0.9 0.8 ;...
    3 4 1.1 2.2]}        

Answer 1

[Stephen23]

A general solution in one line:

C = cellfun(@(r)A(r,:),B,'uni',0)

Answer 2

[madhan ravi]

A=[1 2 0.1 0.2;...
   1 5 0.2 0.2;...
   2 3 0.4 0.4;...
   2 4 0.9 0.8;...
   2 5 0.3 0.4;...
   3 4 1.1 2.2];
B={[1,2,5],[3,4,6]}; 
C{1}=A(B{1},:);
C{2}=A(B{2},:);
celldisp(C)

Gives:

C{1} =
 
    1.0000    2.0000    0.1000    0.2000
    1.0000    5.0000    0.2000    0.2000
    2.0000    5.0000    0.3000    0.4000
 
C{2} =
 
    2.0000    3.0000    0.4000    0.4000
    2.0000    4.0000    0.9000    0.8000
    3.0000    4.0000    1.1000    2.2000

[madhan ravi]

Just use it in a loop then?

C=cell(1,numel(B));
for j=1:numel(B)
    C{j}=A(B{j},:);
end
celldisp(C)

Note: It's the one that Guillaume has suggested as the second option.

Answer 3

[Guillaume]

C = cellfun(@(rows) A(rows, :), B, 'UniformOutput', false)

or if you prefer a loop:

C = cell(size(B));
for idx = 1:numel(B)
    C{idx} = A(B{idx}, :);
end