MATLAB Answers

choose 2 index separately inside cell

2 views (last 30 days)
NA on 22 Feb 2019
Edited: NA on 1 Mar 2019
change_amount=cellfun(@(m) m/2, index, 'UniformOutput', false);
p=cellfun(@(m) randperm(size(m,2)), index, 'UniformOutput', false);
changed_mes=cellfun(@(m) m(1:changed_num), p, 'UniformOutput', false);
I do not want repeated index in changed_mes(does not have any intersection). if changed_mes become {[3,9],[9,3],[3,2],[1,4]} as [3,9] and [9,3] is same, need to do randperm again. so I wrote this code
finally i can change amount of 2 mes in each array
result=cellfun(@(m,u) m(u)=0, change_amount,p 'UniformOutput', false);
but does not give correct result

  1 Comment

Jan on 22 Feb 2019
You have posted some code, which does not do, what you want. It is not easy to find out, what you consider as "correct result". It would be much easier if you mention, what you want to achieve actually. What is the wanted result?
The excessive use of cellfun makes it much harder to understand and debug the code. Maybe some simple loops are ways better. Optimize the code with some smart cellfun calls only after you have an already working solution and if you can prove, that it is really faster.

Sign in to comment.

Answers (1)

Jan on 22 Feb 2019
index = {[1,2,5,9,10,13,17,18,21],[4,5,7,12,13,15,18,20,21],[3,4,6,11,12,14,18,19,20],[8,16,20,22]};
amount = {[10,11,12,10,11,10,12,13,20],[11,15,12,13,11,10,15,13,12],[13,16,16,17,11,10,15,13,12],[4,5,6,10]};
num = 2;
result = cell(size(amount));
for k = 1:numel(result)
m = amount{k} / 2;
... ??? I cannot follow the rest of the code
... You want a set of [num] randomly selected indices to be set to 0, correctly?
Sorry, I tried to recreate the code by a simple loop, but failed to understand the logic.


NA on 22 Feb 2019
Simple code is here
p = randperm(size(index,2));
but index and amount is cell.
the other problem is I want to get result that has unique changed_mes_index.
for example 5 is common in first and second index, so if in first index choose 5 and 6 as changed_mes_index, in second one should be anything expect 5.
example of acceptable changed_mes={[1,9],[4,15],[3,12],[16,20]}
do not acceptable changed_mes={[13,17],[5,13],[20,12],[8,20]} as13 and 20 is repeated
Jan on 25 Feb 2019
A clear description of what the code should do would be a good idea, preferrably as comments. A samll simplification:
index = [1,2,5,9,10,13,17,18,21];
amount = [10,11,12,10,11,10,12,13,20];
num = 2;
p = randperm(numel(index));
changed_mes_index = p(1:num);
b = amount / 2;
b(p(num+1:end)) = 0;
result = amount + b;
I have no idea, how this problem can be modified to work with cells.
You go forward with mentioning "the other problem". What exactly is the first problem?
If you want the elements in the cell array changed_mes to be unique, create it accordingly:
num = 2; % a [1x2] vector per cell element
numC = 4; % Number of cell elements
maxV = 20; % The maximum value
V = (1:maxV);
V = V(randperm(maxV, num * numC));
changed_mes = num2cell(reshape(V, [], 2), 2);

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!