matlab error operands to the || and &amp &amp operators must be convertible to logical scalar values

clc;
clear all
close all
%%%
unit=input('input the number of unit:');
D=input('input total load :');
dP=D;
Bdat1=input('transmission losses considered matrix:');
B=Bdat1;
dB=diag(B);
data1=input('input the data:n a b c min max');
DA=array2table(data1,'V',{'Unit' 'a' 'b' 'c' 'Pl' 'Ph'});
x=max(DA.b);
n=input('insert number of iteration:');
for i=1:n
    while abs(dP)>0.00001
        P=(x-DA.b)./(2*(DA.c+x*dB));
        P=min(P,DA.Ph);
        P=max(P,DA.Pl);
        dP=D+P'*B*P-sum(P);
        x=x+dP*2/(sum(1./DA.c));
    end
end

 if (P< DA.Pl) | (P > DA.Ph)
     P=0;
    
 end

C=DA.a+DA.b.*P+DA.c.*P.*P;
totalCost=sum(C);
display(P);
display(totalCost);
lamda=x;
display(lamda);
Loss=P'*B*P;
display(Loss);
display(C);
display(P);

if i insert the data :Unit=3

Total load=850

Bdat1=[0.00003 0 0;0 0.00009 0;0 0 0.00012]

data1=[1 605 7.92 0.001562 700 800; 2 310 7.785 0.00194 100 400;3 78 7.97 0.00482 50 300]

n=1

i get the value of P=

500.0000

255.4601

109.3481

but i want the the first value of P which is 500 become zero

in general if one P less than min or greater than max set this P=0

[Walter Roberson]

Which line of code is the error on? You do not have any && or || in the code you posted

[Mariam Gasra]

clc;
clear all
close all
%%%
unit=input('input the number of unit:');
D=input('input total load :');
dP=D;
Bdat1=input('transmission losses considered matrix:');
B=Bdat1;
dB=diag(B);
data1=input('input the data:n a b c min max');
DA=array2table(data1,'V',{'Unit' 'a' 'b' 'c' 'Pl' 'Ph'});
x=max(DA.b);
n=input('insert number of iteration:');
for i=1:n
    while abs(dP)>0.00001
        P=(x-DA.b)./(2*(DA.c+x*dB));
        P=min(P,DA.Ph);
        P=max(P,DA.Pl);
        dP=D+P'*B*P-sum(P);
        x=x+dP*2/(sum(1./DA.c));
    end
end
if P < DA.Ph || P > DA.Pl
    P = 0;
end
C=DA.a+DA.b.*P+DA.c.*P.*P;
totalCost=sum(C);
display(P);
display(totalCost);
lamda=x;
display(lamda);
Loss=P'*B*P;
display(Loss);
display(C);
display(P);

Answer 1

[Andrei Bobrov]

Use

P(P< DA.Pl) | (P > DA.Ph) = 0;

instead

if (P< DA.Pl) | (P > DA.Ph)
    P=0;
end

[Walter Roberson]

() are in the wrong place Andrei

[Mariam Gasra]

thanks alot

the error was solve but So far, I have not received a value of zero instead of 500

[Walter Roberson]

DA.Pl and DA.Ph are each vectors. What do you want it to mean to test values against those vectors?

Is the logic to follow that each element of P must be between one of the pairs? So in your data1 that uses [700 800; 100 400; 50 300] then you want to check to see whether (P >= 700 and P <= 800) or (P >= 100 and P<=400) or (P>=50 and P<=300) ? That is, it is to be accepted if it falls within any of the intervals and otherwise rejected ?

[Mariam Gasra]

Yes this what I mean Check for that and accept if within the limits and set it equal zero if its not

[Walter Roberson]

Your P is calculated from DA.b and DA.c, both of which are vectors, so your P will be a vector.

It would look to me to make more sense to check to see whether P is within the corresponding range for that element, rather than it being within any of the ranges.

However, I think Andrei's solution of

P(P < DA.Pl | P > DA.Ph) = 0;

should be all that is needed.

You talk about the value of P being 500, but P is going to be a vector, and whether 500 is valid or not would depend upon the row.

[Mariam Gasra]

I went p = 0 299.1984 130.6606 Reject first element because its not within the limt

Answer 2

[Andrei Bobrov]

Thanks Walter! My typo.

Use

P((P< DA.Pl) | (P > DA.Ph)) = 0;

instead

if (P< DA.Pl) | (P > DA.Ph)
    P=0;
end

[Mariam Gasra]

if i use this code P((P< DA.Pl) | (P > DA.Ph)) = 0;

the value of P=500 but i want it equal zero

if i use P((P> DA.Pl) | (P < DA.Ph)) = 0;

i get all value of P equal zero