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How to know dimensions to give in trapz function

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Hi,
Let's say I have a matrix (see below). How do I know what number to put in the dimension variable? Matlab just gives some odd explanation without telling how to determine the dimension. Could someone please help to understand how to get the value for dim?
[Kx, W, Ky] = meshgrid(kx, w, ky);
for j = 1:9;
functione = exp(-((W-w_o).^2)/deltaW.^2).*exp(-(Kx.^2+Ky.^2)/(deltaK.^2)).*exp(1i.*sqrt((W/c).^2-(Kx.^2+Ky.^2)).*z(j));
normw = trapz(functione.^2,dim)*dw
normkx = trapz(functione.^2,dim)*dkx
normky = trapz(functione.^2,dim)*dky
  2 Comments
TADA
TADA on 11 Jul 2019
It is up to you along which dimension you want it to integrate

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Answers (1)

TADA
TADA on 11 Jul 2019
let's say you have a column vector x and you calculate y according to y = ax^2
now if a is a vector, you will get a matrix y:
x = linspace(0,10,5)';
a = [1 10 100];
y = a.*(x.^2)
y =
1.0e+04 *
0 0 0
0.0006 0.0063 0.0625
0.0025 0.0250 0.2500
0.0056 0.0563 0.5625
0.0100 0.1000 1.0000
This y matrix represents 3 possible column vectors ax^2 with different parameter value
Now to integrate correctoly, you should integrate along the first dimension (same dimension as the x column vector)
dim = 1;
A = trapz(x,y,dim)
A =
1.0e+04 *
0.0344 0.3438 3.4375
  7 Comments
J K
J K on 12 Jul 2019
I understand it all now. Thank you so much for your extensive answers!

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