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Why I got the error "Undefined operator '.*' for input arguments of type 'function_handle"?

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Aimi Oguri
Aimi Oguri on 19 Jan 2020
Answered: Steven Lord on 19 Jan 2020
RCac = @(~,state) (-k4.*(state.u(1)./K3+state.u(1)).^2+...
k3.*state.u(1)./(KCICR+state.u).*(IP3./(IP3+K2)).^3.*Cas)...
-kon.*state.u(1).*(BT-CaB)+koff.*CaB;
s = @(x, y) RCac;
Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...
wOmega(2) * PhiIPS(:, 2) .* s(ip(2, 1), ip(2, 2)) * areaOfElement + ...
wOmega(3) * PhiIPS(:, 3) .* s(ip(3, 1), ip(3, 2)) * areaOfElement;
I keep receiving the error message:
'function_handle' 型の入力引数の演算子 '.*' が未定義です。
エラー: BarbeeModel (line 159)
Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...
in English:
Undefined operator '.*' for input arguments of type 'function_handle'.
Error in
Fe = wOmega(1) * PhiIPS(:, 1) .* s(ip(1, 1), ip(1, 2)) * areaOfElement + ...

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Accepted Answer

Steven Lord
Steven Lord on 19 Jan 2020
You can't multiply a function handle, which is what s returns. If you intend s to evaluate the function handle RCac, just make it an alias of that function handle.
s = RCac;
Or if you wanted to make it explicit in that line of code that s is a function handle:
s = @(x, y) RCac(x, y);
In either of these cases s(something, somethingElse) returns a number rather than a function handle, and you can multiply a number by another number.

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