How to get underlying numbers of enumeration?

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I have a custom enumeration data type such as the one defined in the code below. How can I get the underlying integer values that comprise the type (i.e., [0,1,2])?
Simulink.defineIntEnumType('BasicColors', {'Red', 'Yellow', 'Blue'}, [0;1;2])
The getEnumTypeInfo function does not provide this information. The class metadata provides the EnumerationMemberList, but not the numerical values. Is there any other way?

Accepted Answer

Fangjun Jiang
Fangjun Jiang on 26 Feb 2020
Simulink.defineIntEnumType('BasicColors', {'Red', 'Yellow', 'Blue'}, [0;1;2]);
a=BasicColors.Blue;
a.real
  6 Comments
riccardo
riccardo on 9 Nov 2020
I'm using 2020a.
Once you have an EnumTypeDefinition object in the main workspace, one of the properties is "Enumerals".
>> enumDefList = <enumTypeDefObject>.Enumerals;
will return in "enumDefList" a structure array holding Name, Value and Description of the enumerated type.
Alternatively, if you define the object in Matlab:
>>Simulink.defineIntEnumType( 'tryEnum01', { 'AA', 'BB', 'CC', 'KK' }, [0, 2 , 4, 6] )
using enumeration you extract the arrays of enumerated definitions and labels :
>> [ gg, hh ] = enumeration( 'tryEnum01' );
scalar-expanding the enumerated definitions "gg" within a cast to double:
>> indexes = double( gg(:) )
indexes =
0
2
4
6
<<
If you want just the numerical values, then
>> indexes = double( enumeration( 'tryEnum01' ) )
indexes =
0
2
4
6

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