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for loop of vector

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fima v
fima v on 6 May 2020
Commented: fima v on 6 May 2020
Hello, i have a function shown bellow called fun, i want to sample it in a 10.^-6 - 20*10.^-6 interval with 1000 samples as shown bellow.
I have tried to implement it as following with a for loop as shown bellow,but its not iterating over the range where did i go wrong?
Thanks.
c0=2.997*10.^8;
h=6.625*10.^-34;
k=1.38*10.^-23;
n=1;
T=307;
filter=linspace(1,1,1000);
fun=@(lambda)(2*pi.*h.*(c0.^2))./((lambda.^5).*(exp((h.*c0)./(k.*T.*lambda))-1));
for k=linspace(1*10.^-6,20*10.^-6,1000);
plank_vec=fun(k);
end

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Accepted Answer

KSSV
KSSV on 6 May 2020
You need not to use loop for this:
c0=2.997*10.^8;
h=6.625*10.^-34;
k=1.38*10.^-23;
n=1;
T=307;
filter=linspace(1,1,1000);
fun=@(lambda)(2*pi.*h.*(c0.^2))./((lambda.^5).*(exp((h.*c0)./(k.*T.*lambda))-1));
k=linspace(1*10.^-6,20*10.^-6,1000);
plank_vec=fun(k);
If you want to use loop:
plank_vec = zeros(1,length(k)) ;
for i = 1:length(k) ;
plank_vec(i)=fun(k(i));
end

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fima v
fima v on 6 May 2020
Thank you very much.

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