# create a matrix with a for loop

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Adam Levschuk on 18 Jun 2020
Commented: Adam Levschuk on 18 Jun 2020
Hello all, i am trying to calculate a bunch of matrices using a for loop. I have written the following code
T = 60;
for t = 60:60:12940
phi(:,t) = [(n1(1,t+T)-n2(1,t+T)) / (n1(1,t)-n2(1,t)), (n3(1,t+T)-n4(1,t+T)) / (n3(2,t)-n4(2,t)); (n1(2,t+T)-n2(2,t+T)) / (n1(1,t)-n2(1,t)), (n3(2,t+T)-n4(2,t+T)) / (n3(2,t)-n4(2,t))];
end
i am getting an error code that says the left side of the equation is a 2-by-1 and the right side is a 2-by-2. both sides of the equation are supposed to be a 2-by-2!
How would i go about writing the left side of the eqution so it would work with the for loop and result in a 2-by-2?
Thanks for any help!

KSSV on 18 Jun 2020
Edited: KSSV on 18 Jun 2020
T = 60;
phi = cell([],1) ;
count = 0 ;
for t = 60:60:12940
count = count+1 ;
phi{count} = [(n1(1,t+T)-n2(1,t+T)) / (n1(1,t)-n2(1,t)), (n3(1,t+T)-n4(1,t+T)) / (n3(2,t)-n4(2,t)); (n1(2,t+T)-n2(2,t+T)) / (n1(1,t)-n2(1,t)), (n3(2,t+T)-n4(2,t+T)) / (n3(2,t)-n4(2,t))];
end
If you think that always the RHS is a 2x2 matrix, ot can be saved into matrix by initlaizing it into a 3D matrix.

Adam Levschuk on 18 Jun 2020
n1 is a 2x12000 array. same with n2, n3, and n4. What do you think?
Thank you so much for your help,
KSSV on 18 Jun 2020
Then you see...you are accessing 12940....it is clear....
You can access elements only upto index 12000....you need to change the loop indexing.
Adam Levschuk on 18 Jun 2020
such a silly mistake -- thanks you so much for the help KSSV.
Very much appreciated!!!

madhan ravi on 18 Jun 2020
T = 60;
phi = cell(numel(t),1);
t = 60:60:12940;
for k = 1:numel(t)
phi{k} = [(n1(1,t(k)+T)-n2(1,t(k)+T)) / ...
(n1(1,t(k))-n2(1,t(k))), (n3(1,t(k)+T)-n4(1,t(k)+T)) / ...
(n3(2,t(k))-n4(2,t(k))); (n1(2,t(k)+T)-n2(2,t(k)+T)) / ...
(n1(1,t(k))-n2(1,t(k))), (n3(2,t(k)+T)-n4(2,t(k)+T)) / (n3(2,t(k))-n4(2,t(k)))];
end
celldisp(phi)
phi = cat(3,phi{:})

Adam Levschuk on 18 Jun 2020
Hello madhan, i am getting an error code taht says,
"Index in position 2 exceeds array bounds (must not exceed 12000)."
ive never undertsood this error code when making for loops. Any idea of how this would be solved??
thank you so much for your help!
madhan ravi on 18 Jun 2020
I don’t have time to get into details here but to illustrate with an example:
x = rand(2,2)% has two columns
x(1,3) % but you’re trying to access the third column, which doesn’t make sense
Adam Levschuk on 18 Jun 2020

R2020a

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