findpeak for every column of a matrix

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i have one issue, i have matrix 760x5 how to findpeaks for every column without having to write findpeak in each column
this is the example coding that I used :
[pks1_p,loc1_p] = findpeaks(y_p(:,1),'MinPeakHeight',0.09,'MinPeakDistance',100);
[pks2_p,loc2_p] = findpeaks(y_p(:,2),'MinPeakHeight',0.09,'MinPeakDistance',100);
[pks3_p,loc3_p] = findpeaks(y_p(:,3),'MinPeakHeight',0.09,'MinPeakDistance',100);
[pks4_p,loc4_p] = findpeaks(y_p(:,4),'MinPeakHeight',0.09,'MinPeakDistance',100);
[pks5_p,loc5_p] = findpeaks(y_p(:,5),'MinPeakHeight',0.09,'MinPeakDistance',100);
the problem is I have to write findpeak one by one to see the value of each column. how to get findpeak to follow the number of columns that exist without having to be written one by one
but I need values ​​from pks and loc of each column in the workspace :

Accepted Answer

Mohammad Sami
Mohammad Sami on 27 Jul 2020
You can use size(y_p,2) to find how many columns there are in your data.
Thereafter you can either use a for loop or arrayfun to iterate over the columns.
[pks_p,loc_p] = arrayfun(@(col)findpeaks(y_p(:,col),'MinPeakHeight',0.09,'MinPeakDistance',100),1:size(y_p,2),'UniformOutput',false);
% pks_p, loc_p would be cell arrays. index 1 will correspond to column 1 and so on
  3 Comments
Mohammad Sami
Mohammad Sami on 27 Jul 2020
you mean you want them to appear in workspace ?
i would suggest use indexing to access the data from each col.
% example
for i = 1:length(pks_p)
pksi_p = pks_p{i};
loci_p = loc_p{i};
% do something
end
Rafi.P
Rafi.P on 27 Jul 2020
Thank you Mohammad Sami

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More Answers (1)

Steven Lord
Steven Lord on 27 Jul 2020
Consider using islocalmax with the dim input argument.

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