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How do I count the number of all color pixels of different shades in the image attached?

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Atique Khan
Atique Khan on 28 Aug 2020
Commented: Jakob on 28 Aug 2020
The picture attached is 256x256 represents the regions of different colors. When I use the color pixel count using the following code that doesn't give the correct counts of each pixel color when I sum up the whole counts it ends up 50333 but I think it should be 65536. Kindly help to correct the code as I think where there are region boundaries the color intensities are changing thats why the counts are not correct and if its so then how can I manage?
clc;
clear;
close all;
I = imread('B001.png');
YellowPixelsI = I(:,:,1) == 255 & I(:,:,2) == 255 & I(:,:,3) == 0;
numYellowPixelsI = sum(YellowPixelsI(:));
LimePixelsI = I(:,:,1) == 0 & I(:,:,2) == 127 & I(:,:,3) == 0;
numLimePixelsI = sum(LimePixelsI(:));
GreenPixelsI = I(:,:,1) == 0 & I(:,:,2) == 255 & I(:,:,3) == 0;
numGreenPixelsI = sum(GreenPixelsI(:));
IndigoPixelsI = I(:,:,1) == 74 & I(:,:,2) == 0 & I(:,:,3) == 129;
numIndigoPixelsI = sum(IndigoPixelsI(:));
TealPixelsI = I(:,:,1) == 0 & I(:,:,2) == 127 & I(:,:,3) == 127;
numTealPixelsII = sum(TealPixelsI(:));
RedPixelsI = I(:,:,1) == 255 & I(:,:,2) == 0 & I(:,:,3) == 0;
numRedPixelsI = sum(RedPixelsI(:));
BrownPixelsI = I(:,:,1) == 164 & I(:,:,2) == 41 & I(:,:,3) == 41;
numBrownPixelsI = sum(BrownPixelsI(:));
BluePixelsI = I(:,:,1) == 0 & I(:,:,2) == 0 & I(:,:,3) == 255;
numBluePixelsI = sum(BluePixelsI(:));
CyanPixelsI = I(:,:,1) == 0 & I(:,:,2) == 255 & I(:,:,3) == 255;
numCyanPixelsI = sum(CyanPixelsI(:));
MagentaPixelsI = I(:,:,1) == 255 & I(:,:,2) == 0 & I(:,:,3) == 255;
numMagentaPixelsI = sum(MagentaPixelsI(:));
WhitePixelsI = I(:,:,1) == 255 & I(:,:,2) == 255 & I(:,:,3) == 255;
numWhitePixelsI = sum(WhitePixelsI(:));

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Accepted Answer

Jakob
Jakob on 28 Aug 2020
numYellowPixelsI= size(find((I(:,:,1) == 255 & I(:,:,2) == 255 & I(:,:,3) == 0)),1);
In this case there would be 7025 yellow Pixel. Hope this helps

  1 Comment

Jakob
Jakob on 28 Aug 2020
[a,b] = find((I(:,:,1) == 255 & I(:,:,2) == 255 & I(:,:,3) == 0));
gives you the exact postion of each yellow Pixel

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