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How do I stop the calculation in a for loop?

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gamer
gamer on 13 Jun 2021
Commented: gamer on 14 Jun 2021
Hello community!
First of all thanks for your help:)
n = 4;
v = rand(n,2);
for f = 1:1000
v = v-0.001
end
Thats already what I ve got. It gives me 1000 of matrixes back and alyways calculated by - 0.001. Now I ve got problem. If one element of the matrix (for example matrix Number 94) is already smaller than 0.001, then this element should be for all other matrixes ( 95 - 1000) equal to zero. I hope you have some advice! Thanks.

Accepted Answer

Walter Roberson
Walter Roberson on 13 Jun 2021
The division by 50 is just to make the output shorter for this demonstration.
format long g
n = 4;
v = rand(n,2) / 50;
for f = 2:1000
temp = v - 0.001;
temp(temp < 0.001) = 0;
v = temp
if ~any(v(:)); break; end %all 0
end
v = 4×2
0.0117169155857542 0.00385373115144157 0.00322072350669969 0.0123980988902088 0.00540972017890342 0.00679499574461224 0.0119082492555772 0
v = 4×2
0.0107169155857542 0.00285373115144157 0.00222072350669969 0.0113980988902088 0.00440972017890342 0.00579499574461224 0.0109082492555772 0
v = 4×2
0.00971691558575421 0.00185373115144157 0.00122072350669969 0.0103980988902088 0.00340972017890342 0.00479499574461224 0.00990824925557724 0
v = 4×2
0.00871691558575421 0 0 0.00939809889020883 0.00240972017890342 0.00379499574461224 0.00890824925557724 0
v = 4×2
0.00771691558575421 0 0 0.00839809889020883 0.00140972017890342 0.00279499574461224 0.00790824925557724 0
v = 4×2
0.00671691558575421 0 0 0.00739809889020883 0 0.00179499574461224 0.00690824925557724 0
v = 4×2
0.00571691558575421 0 0 0.00639809889020883 0 0 0.00590824925557724 0
v = 4×2
0.00471691558575421 0 0 0.00539809889020883 0 0 0.00490824925557724 0
v = 4×2
0.00371691558575421 0 0 0.00439809889020883 0 0 0.00390824925557724 0
v = 4×2
0.00271691558575421 0 0 0.00339809889020883 0 0 0.00290824925557724 0
v = 4×2
0.00171691558575421 0 0 0.00239809889020883 0 0 0.00190824925557724 0
v = 4×2
0 0 0 0.00139809889020883 0 0 0 0
v = 4×2
0 0 0 0 0 0 0 0
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