Should sympref Change the Behavior of rectangularPulse()?

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  • If x = a or x = b and a <> b, then the rectangular pulse function equals 1/2.
Verify this statement:
rectangularPulse(0,1,[0 1])
ans = 1×2
0.5000 0.5000
syms t real
h(t) = heaviside(t) - heaviside(t-1);
h([0 1])
ans = 
But changing the sympref for HeavisideAtOrigin yields:
sympref('HeavisideAtOrigin',sym(1));
rectangularPulse(0,1,[0 1])
ans = 1×2
1 1
h([0 1])
ans = 
So rectangularPulse appears to not be the difference between heavisides. But the sympref('HeavisideAtOrigin') does impact the edge values of rectangularPulse. Is this expected behavior and a deficiency in the documentation?
  2 Comments
Walter Roberson
Walter Roberson on 1 Aug 2021
By the way, you can see the actual code by using
regexprep(char(evalin(symengine, 'expose(rectangularPulse)')),'\\n','\n')
but it is not straight forward.
Paul
Paul on 1 Aug 2021
After running that command, it sure looks like that under "normal" conditions, the edge values are heaviside(0). So that would be an oversight in the documentation.

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