How to convert a minutes elapsed vector to time (hh:mm)?

Hi,

On a continous 24 hour measurement, I have a vector of time elapsed in minutes since the beginning (0 to 1440). I know that the starting time of the measurement is 16:00. How to create a time vector (hh:mm) for each sample? The purpose is to add the time on the x axis of a plot.

My best try is using a loop that goes through each sample, with h (hour) starting at 16 and rounds the minutes. The issue is it must detect every hour change.

Looking forward for some help :)

for i=1:length(meas_SPL_all)
    meas_SPL_all(:,3) = {h:round(meas_SPL_all(i,2))}
    if round(meas_SPL_all(i,2) > 60
        h = h + 1
end

Answer 1

[Walter Roberson]

t = hours(16) + minutes(meas_SPL_all(:, 2));
t.Format = 'hh:mm';

[Antonio Taveira]

Works great! Thanks, Walter.

Answer 2

[Peter Perkins]

"continous 24 hour measurement" sounds like you are dealing with time of day. If you add 600 minutes to hours(16), you will get

>> hours(16) + minutes(600)
ans = 
  duration
   26 hr

which may not be what you want. If you want this to wrap to 04:00, add to an absolute time.

>> datetime(2021,8,9,16,0,0) + minutes(600)
ans = 
  datetime
   10-Aug-2021 02:00:00