Cody

# Problem 30. Sort a list of complex numbers based on far they are from the origin.

Solution 3258368

Submitted on 18 Oct 2020 by Graham Greig
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### Test Suite

Test Status Code Input and Output
1   Pass
j = sqrt(-1); z = [-4 6 3+4*j 1+j 0]; zSorted_correct = [6 3+4*j -4 1+j 0]; assert(isequal(complexSort(z),zSorted_correct))

zsorted = 6.0000 + 0.0000i 6.0000 + 0.0000i 3.0000 + 4.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i index = 2 z = -4.0000 + 0.0000i 3.0000 + 4.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i zsorted = 6.0000 + 0.0000i 3.0000 + 4.0000i 3.0000 + 4.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i index = 2 z = -4.0000 + 0.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i zsorted = 6.0000 + 0.0000i 3.0000 + 4.0000i -4.0000 + 0.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i index = 1 z = 1.0000 + 1.0000i 0.0000 + 0.0000i zsorted = 6.0000 + 0.0000i 3.0000 + 4.0000i -4.0000 + 0.0000i 1.0000 + 1.0000i 0.0000 + 0.0000i index = 1 z = 0

2   Pass
z = 1:10; zSorted_correct = 10:-1:1; assert(isequal(complexSort(z),zSorted_correct))

zsorted = 10 2 3 4 5 6 7 8 9 10 index = 10 z = 1 2 3 4 5 6 7 8 9 zsorted = 10 9 3 4 5 6 7 8 9 10 index = 9 z = 1 2 3 4 5 6 7 8 zsorted = 10 9 8 4 5 6 7 8 9 10 index = 8 z = 1 2 3 4 5 6 7 zsorted = 10 9 8 7 5 6 7 8 9 10 index = 7 z = 1 2 3 4 5 6 zsorted = 10 9 8 7 6 6 7 8 9 10 index = 6 z = 1 2 3 4 5 zsorted = 10 9 8 7 6 5 7 8 9 10 index = 5 z = 1 2 3 4 zsorted = 10 9 8 7 6 5 4 8 9 10 index = 4 z = 1 2 3 zsorted = 10 9 8 7 6 5 4 3 9 10 index = 3 z = 1 2 zsorted = 10 9 8 7 6 5 4 3 2 10 index = 2 z = 1

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