Problem 661. Spot the outlier

Solution 2045741

Submitted on 4 Dec 2019 by Miles Walker

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Miles Walker on 4 Dec 2019

Uses the formula for perpendicular distance of a point to a line when the line is not axis orthogonal.

Test	Status	Code Input and Output
1	Pass	pts = [0 1; 0 2; 3 2; 0 3; 0 4 ]; outlier = 3; assert(isequal(spot_the_outlier(pts),outlier))
2	Pass	pts = [10 -1;7 0;9.5 0.3;9 1.6;8.5 2.9]; outlier = 2; assert(isequal(spot_the_outlier(pts),outlier))
3	Pass	pts = [-0.6 -6;-0.2 0;0 3;-0.8 -9;-2 1;-0.4 -3]; outlier = 5; assert(isequal(spot_the_outlier(pts),outlier))
4	Pass	pts = [2 5;0 4;0 0;4 6;-2 3]; outlier = 3; assert(isequal(spot_the_outlier(pts),outlier))
5	Pass	pts = [1 0; 0 1; 1 2; 1.5 2.5; 2 3; 3 4 ]; outlier = 1; assert(isequal(spot_the_outlier(pts),outlier))