Cody

# Problem 71. Read a column of numbers and interpolate missing data

Solution 2056600

Submitted on 13 Dec 2019 by Jean-Baptiste Roquebert
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### Test Suite

Test Status Code Input and Output
1   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 -32' ' 5 13' ' 6 4.4' ' 7 19'}; t_correct = [1.3 1.12 17 -32 13 4.4 19]; assert(isequal(read_and_interp(s),t_correct));

t = 1×8 cell array {' Temp'} {' 1.3'} {' 1.12'} {' 17'} {' -32'} {' 13'} {' 4.4'} {' 19'} t = 1.3000 1.1200 17.0000 -32.0000 13.0000 4.4000 19.0000 c = 1×0 empty double row vector d = 1×0 empty double row vector

2   Pass
s = { ... 'Day Temp' ' 1 1.3' ' 2 1.12' ' 3 17' ' 4 16' ' 5 9999' ' 6 9999' ' 7 19'}; t_correct = [1.3 1.12 17 16 17 18 19]; assert(isequal(read_and_interp(s),t_correct));

t = 1×8 cell array {' Temp'} {' 1.3'} {' 1.12'} {' 17'} {' 16'} {' 9999'} {' 9999'} {' 19'} t = 1.0e+03 * 0.0013 0.0011 0.0170 0.0160 9.9990 9.9990 0.0190 c = 5 d = 6 t = 1.3000 1.1200 17.0000 16.0000 17.0000 18.0000 19.0000

3   Pass
s = { ... 'Day Temp' ' 1 -5' ' 2 19' ' 3 1' ' 4 9999' ' 5 3'}; t_correct = [-5 19 1 2 3]; assert(isequal(read_and_interp(s),t_correct));

t = 1×6 cell array {' Temp'} {' -5'} {' 19'} {' 1'} {' 9999'} {' 3'} t = -5 19 1 9999 3 c = 4 d = 4 t = -5 19 1 2 3