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The numbers you put in x will be linearly interpolated.\r\n\r\nFor example, if x=[1 5 2 4 3] and n=1, your output should be:\r\n\r\ny=[1 3 5 3.5 2 3 4 3.5 3]\r\n\r\nThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\r\n\r\n* 1 --\u003e 3 --\u003e 5\r\n* 5 --\u003e  3.5  --\u003e 2\r\n* 2 --\u003e 3 --\u003e 4\r\n* 4 --\u003e 3.5 --\u003e 3","description_html":"\u003cp\u003eYou will be given a row of numbers (x), and a single number (n).  Your job is to write a script that will stretch out the row of numbers, putting n numbers between each of the numbers in x.  The numbers you put in x will be linearly interpolated.\u003c/p\u003e\u003cp\u003eFor example, if x=[1 5 2 4 3] and n=1, your output should be:\u003c/p\u003e\u003cp\u003ey=[1 3 5 3.5 2 3 4 3.5 3]\u003c/p\u003e\u003cp\u003eThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\u003c/p\u003e\u003cul\u003e\u003cli\u003e1 --\u0026gt; 3 --\u0026gt; 5\u003c/li\u003e\u003cli\u003e5 --\u0026gt;  3.5  --\u0026gt; 2\u003c/li\u003e\u003cli\u003e2 --\u0026gt; 3 --\u0026gt; 4\u003c/li\u003e\u003cli\u003e4 --\u0026gt; 3.5 --\u0026gt; 3\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = stretch_it_out(x,n)\r\n  y = x.*n;\r\nend","test_suite":"%%\r\nx = [1 5 2 4 3];n=1;\r\ny_correct = [1 3 5 3.5 2 3 4 3.5 3];\r\nassert(isequal(stretch_it_out(x,n),y_correct))\r\n%%\r\nx = [1 5 2 4 3];n=2;\r\ny_correct=[1 2+1/3 3+2/3 5 4 3 2 2+2/3 3+1/3 4 3+2/3 3+1/3 3];\r\ny=abs(stretch_it_out(x,n)-y_correct);\r\nassert(max(y)\u003c1e-9)\r\n%%\r\nk=ceil(5*rand)+1\r\nx=1:k:121\r\nn=k-1;\r\nassert(isequal(stretch_it_out(x,n),1:121))\r\n%%\r\nx=[1 -1 1 -1 1 -1 1];n=3;\r\ny_correct=[1 0.5  0 -0.5 -1 -0.5  0 0.5  1 0.5  0 -0.5 -1 -0.5  0 0.5  1 0.5  0 -0.5 -1 -0.5  0 0.5  1];\r\nassert(isequal(stretch_it_out(x,n),y_correct))","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":79,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":43,"created_at":"2016-09-20T17:08:32.000Z","updated_at":"2025-12-23T03:42:27.000Z","published_at":"2016-09-20T17:09:01.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou will be given a row of numbers (x), and a single number (n). Your job is to write a script that will stretch out the row of numbers, putting n numbers between each of the numbers in x. The numbers you put in x will be linearly interpolated.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example, if x=[1 5 2 4 3] and n=1, your output should be:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ey=[1 3 5 3.5 2 3 4 3.5 3]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e1 --\u0026gt; 3 --\u0026gt; 5\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e5 --\u0026gt; 3.5 --\u0026gt; 2\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e2 --\u0026gt; 3 --\u0026gt; 4\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId w:val=\\\"1\\\"/\u003e\u003c/w:numPr\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003e4 --\u0026gt; 3.5 --\u0026gt; 3\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003c/w:body\u003e\u003c/w:document\u003e\"},{\"partUri\":\"/matlab/output.xml\",\"contentType\":\"text/xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\" standalone=\\\"no\\\" ?\u003e\u003cembeddedOutputs\u003e\u003cmetaData\u003e\u003cevaluationState\u003emanual\u003c/evaluationState\u003e\u003clayoutState\u003ecode\u003c/layoutState\u003e\u003coutputStatus\u003eready\u003c/outputStatus\u003e\u003c/metaData\u003e\u003coutputArray type=\\\"array\\\"/\u003e\u003cregionArray type=\\\"array\\\"/\u003e\u003c/embeddedOutputs\u003e\"}]}"}],"problem_search":{"errors":[],"problems":[{"id":42992,"title":"S-T-R-E-T-C-H   I-T   O-U-T","description":"You will be given a row of numbers (x), and a single number (n).  Your job is to write a script that will stretch out the row of numbers, putting n numbers between each of the numbers in x.  The numbers you put in x will be linearly interpolated.\r\n\r\nFor example, if x=[1 5 2 4 3] and n=1, your output should be:\r\n\r\ny=[1 3 5 3.5 2 3 4 3.5 3]\r\n\r\nThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\r\n\r\n* 1 --\u003e 3 --\u003e 5\r\n* 5 --\u003e  3.5  --\u003e 2\r\n* 2 --\u003e 3 --\u003e 4\r\n* 4 --\u003e 3.5 --\u003e 3","description_html":"\u003cp\u003eYou will be given a row of numbers (x), and a single number (n).  Your job is to write a script that will stretch out the row of numbers, putting n numbers between each of the numbers in x.  The numbers you put in x will be linearly interpolated.\u003c/p\u003e\u003cp\u003eFor example, if x=[1 5 2 4 3] and n=1, your output should be:\u003c/p\u003e\u003cp\u003ey=[1 3 5 3.5 2 3 4 3.5 3]\u003c/p\u003e\u003cp\u003eThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\u003c/p\u003e\u003cul\u003e\u003cli\u003e1 --\u0026gt; 3 --\u0026gt; 5\u003c/li\u003e\u003cli\u003e5 --\u0026gt;  3.5  --\u0026gt; 2\u003c/li\u003e\u003cli\u003e2 --\u0026gt; 3 --\u0026gt; 4\u003c/li\u003e\u003cli\u003e4 --\u0026gt; 3.5 --\u0026gt; 3\u003c/li\u003e\u003c/ul\u003e","function_template":"function y = stretch_it_out(x,n)\r\n  y = x.*n;\r\nend","test_suite":"%%\r\nx = [1 5 2 4 3];n=1;\r\ny_correct = [1 3 5 3.5 2 3 4 3.5 3];\r\nassert(isequal(stretch_it_out(x,n),y_correct))\r\n%%\r\nx = [1 5 2 4 3];n=2;\r\ny_correct=[1 2+1/3 3+2/3 5 4 3 2 2+2/3 3+1/3 4 3+2/3 3+1/3 3];\r\ny=abs(stretch_it_out(x,n)-y_correct);\r\nassert(max(y)\u003c1e-9)\r\n%%\r\nk=ceil(5*rand)+1\r\nx=1:k:121\r\nn=k-1;\r\nassert(isequal(stretch_it_out(x,n),1:121))\r\n%%\r\nx=[1 -1 1 -1 1 -1 1];n=3;\r\ny_correct=[1 0.5  0 -0.5 -1 -0.5  0 0.5  1 0.5  0 -0.5 -1 -0.5  0 0.5  1 0.5  0 -0.5 -1 -0.5  0 0.5  1];\r\nassert(isequal(stretch_it_out(x,n),y_correct))","published":true,"deleted":false,"likes_count":0,"comments_count":0,"created_by":1615,"edited_by":null,"edited_at":null,"deleted_by":null,"deleted_at":null,"solvers_count":79,"test_suite_updated_at":null,"rescore_all_solutions":false,"group_id":43,"created_at":"2016-09-20T17:08:32.000Z","updated_at":"2025-12-23T03:42:27.000Z","published_at":"2016-09-20T17:09:01.000Z","restored_at":null,"restored_by":null,"spam":false,"simulink":false,"admin_reviewed":false,"description_opc":"{\"relationships\":[{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/document\",\"targetMode\":\"\",\"relationshipId\":\"rId1\",\"target\":\"/matlab/document.xml\"},{\"relationshipType\":\"http://schemas.mathworks.com/matlab/code/2013/relationships/output\",\"targetMode\":\"\",\"relationshipId\":\"rId2\",\"target\":\"/matlab/output.xml\"}],\"parts\":[{\"partUri\":\"/matlab/document.xml\",\"relationship\":[],\"contentType\":\"application/vnd.mathworks.matlab.code.document+xml\",\"content\":\"\u003c?xml version=\\\"1.0\\\" encoding=\\\"UTF-8\\\"?\u003e\\n\u003cw:document xmlns:w=\\\"http://schemas.openxmlformats.org/wordprocessingml/2006/main\\\"\u003e\u003cw:body\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eYou will be given a row of numbers (x), and a single number (n). Your job is to write a script that will stretch out the row of numbers, putting n numbers between each of the numbers in x. The numbers you put in x will be linearly interpolated.\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eFor example, if x=[1 5 2 4 3] and n=1, your output should be:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003ey=[1 3 5 3.5 2 3 4 3.5 3]\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"text\\\"/\u003e\u003c/w:pPr\u003e\u003cw:r\u003e\u003cw:t\u003eThere is n=1 number between all of the original values of x, and the new values are linearly interpolated from the original values of x:\u003c/w:t\u003e\u003c/w:r\u003e\u003c/w:p\u003e\u003cw:p\u003e\u003cw:pPr\u003e\u003cw:pStyle w:val=\\\"ListParagraph\\\"/\u003e\u003cw:numPr\u003e\u003cw:numId 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