3,422 total contributions since 2018

Communication through MATLAB is always better than arguing.

Answered

Swapping the columns based on matrix even length

No matter odd or even: ix=(2:2:size(matrix,2)) + [0;-1]; % if > 2016b ix = bsxfun(@plus, 2:2:size(a,2), [0;-1]) Wanted = matr...

Swapping the columns based on matrix even length

No matter odd or even: ix=(2:2:size(matrix,2)) + [0;-1]; % if > 2016b ix = bsxfun(@plus, 2:2:size(a,2), [0;-1]) Wanted = matr...

3 hours ago | 1

Answered

how to make a legend for a single point

h=plot(i,Cm_1212_voigt,'.g') % inside loop legend(h,'Points') % outside loop

how to make a legend for a single point

h=plot(i,Cm_1212_voigt,'.g') % inside loop legend(h,'Points') % outside loop

1 day ago | 0

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Answered

Delete rows in intervall

An another alternative: ix = (5:7:size(TABLE,1)) + [0;1;2]; %if > 2016b ix = bsxfun(@plus, 5:7:size(TABLE,1), [0;1;2]) TABLE...

Delete rows in intervall

An another alternative: ix = (5:7:size(TABLE,1)) + [0;1;2]; %if > 2016b ix = bsxfun(@plus, 5:7:size(TABLE,1), [0;1;2]) TABLE...

1 day ago | 0

Answered

How can I take a mean of a matrix only from 10 first rows?

>> X = rand(50000,3); % are you sure it's a 50000 by 3 matrix? >> mean(X(1:5000,:)) ans = 0.5028 0.5015 0.4978 ...

How can I take a mean of a matrix only from 10 first rows?

>> X = rand(50000,3); % are you sure it's a 50000 by 3 matrix? >> mean(X(1:5000,:)) ans = 0.5028 0.5015 0.4978 ...

1 day ago | 0

Answered

logical array variables in a loop

It would been simpler if they were stored in a cell array: c{1} = outlier & incl_p; c{2}= outlier & incl_r; c{3} = ou...

logical array variables in a loop

It would been simpler if they were stored in a cell array: c{1} = outlier & incl_p; c{2}= outlier & incl_r; c{3} = ou...

1 day ago | 1

| accepted

Answered

How can i get sub matrices with using for loop

a=arrayfun(@(x)A(A==unique(x)),A,'un',0) celldisp(a) If you’re goal is simply to create A with repetitions of 10 then it...

How can i get sub matrices with using for loop

a=arrayfun(@(x)A(A==unique(x)),A,'un',0) celldisp(a) If you’re goal is simply to create A with repetitions of 10 then it...

2 days ago | 0

Answered

How to count the number of repeat elements in a matrix

M =["Fa" "Fa" "Fa" "Fa" "Ka" "Ka"]; [~,~,c] = unique(M); A = accumarray(c,1)

How to count the number of repeat elements in a matrix

M =["Fa" "Fa" "Fa" "Fa" "Ka" "Ka"]; [~,~,c] = unique(M); A = accumarray(c,1)

2 days ago | 0

Answered

Create a matrix from a vector

A = ismember(M,V) .* M % Note: 14 should be in 1,1 not 2,1

Create a matrix from a vector

A = ismember(M,V) .* M % Note: 14 should be in 1,1 not 2,1

2 days ago | 0

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Answered

Creating a table for publishing for the matrix I defined

TABle = table(T(:),C_vv(:),'VariableNames',{'Temperature','Heat'}) % I don’t know what you mean by naming columns isn’t that V...

Creating a table for publishing for the matrix I defined

TABle = table(T(:),C_vv(:),'VariableNames',{'Temperature','Heat'}) % I don’t know what you mean by naming columns isn’t that V...

3 days ago | 0

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Answered

How to use a nested loop to do a matrix calculation?

x = [1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16] y = [16 15 14 13; 13 14 15 16; 17 18 19 20; 21 22 22 23] v = zeros(k,l)...

How to use a nested loop to do a matrix calculation?

x = [1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16] y = [16 15 14 13; 13 14 15 16; 17 18 19 20; 21 22 22 23] v = zeros(k,l)...

3 days ago | 0

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Answered

How can I add a matrix into another matrix

A = [A;B] help fprintf doc fprintf

How can I add a matrix into another matrix

A = [A;B] help fprintf doc fprintf

3 days ago | 0

Answered

Preallocated array A using a for loop

https://in.mathworks.com/help/matlab/matlab_prog/preallocating-arrays.html - you will see how to store values in each iteration...

Preallocated array A using a for loop

https://in.mathworks.com/help/matlab/matlab_prog/preallocating-arrays.html - you will see how to store values in each iteration...

3 days ago | 2

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Answered

How do i find the x value for a GIVEN x

fsolve(@(x)f(x)-.25,[0,10]) % two solutions but look into you're area of interest fplot(@(x)f(x)-.25,[0,11])

How do i find the x value for a GIVEN x

fsolve(@(x)f(x)-.25,[0,10]) % two solutions but look into you're area of interest fplot(@(x)f(x)-.25,[0,11])

3 days ago | 0

Answered

How to select the values greater than the mean in an array?

B1(B1>mean(B1(:)))

How to select the values greater than the mean in an array?

B1(B1>mean(B1(:)))

3 days ago | 1

| accepted

Answered

Error using ^ inputs

.* .^ <https://in.mathworks.com/help/matlab/matlab_prog/array-vs-matrix-operations.html>

Error using ^ inputs

.* .^ <https://in.mathworks.com/help/matlab/matlab_prog/array-vs-matrix-operations.html>

3 days ago | 0

Answered

How to assign vectors to existing vector

newvector_2=vector_2; ix=nnz(~vector_2); v12=[vector_1,nonzeros(vector_2).']; u=unique(v12); d=setdiff(1:max(v12),v12); new...

How to assign vectors to existing vector

newvector_2=vector_2; ix=nnz(~vector_2); v12=[vector_1,nonzeros(vector_2).']; u=unique(v12); d=setdiff(1:max(v12),v12); new...

3 days ago | 0

Answered

How to add two values to a matrix each five values of that matrix in order to have a new matrix?

ix=arrayfun(@(x)[x,x*(ones(~mod(x,5),2))],1:numel(XY),'un',0); % multiple of 5----^ ^-- n times idx=cat(2,ix{:...

How to add two values to a matrix each five values of that matrix in order to have a new matrix?

ix=arrayfun(@(x)[x,x*(ones(~mod(x,5),2))],1:numel(XY),'un',0); % multiple of 5----^ ^-- n times idx=cat(2,ix{:...

4 days ago | 1

Answered

how to reduce the your matrix output

% Basic indexing: Output(1:end-1)

how to reduce the your matrix output

% Basic indexing: Output(1:end-1)

4 days ago | 0

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Answered

Odd Numbers with missing multiples of a number

I leave the understanding part to the reader to understand whats going on: oddsNoFives=@(x,y)nonzeros((~sum(~mod(1:x,[2;y]),1))...

Odd Numbers with missing multiples of a number

I leave the understanding part to the reader to understand whats going on: oddsNoFives=@(x,y)nonzeros((~sum(~mod(1:x,[2;y]),1))...

4 days ago | 0

Answered

How to do: "for each value of the vector A"

for ii = 1:numel(A) % this is for illustration purposes A(ii) end

How to do: "for each value of the vector A"

for ii = 1:numel(A) % this is for illustration purposes A(ii) end

4 days ago | 0

Answered

"Undefined function" error when using multiple anonymous functions

Define c anonymous function before a_w and everything will be fine.

"Undefined function" error when using multiple anonymous functions

Define c anonymous function before a_w and everything will be fine.

5 days ago | 1

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Answered

Could anyone help me to solve the issue.

NN = num2cell(num2cell(A,2),2)

Could anyone help me to solve the issue.

NN = num2cell(num2cell(A,2),2)

5 days ago | 0

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Answered

Could anyone help me to solve the issue.

Looks like it's the same as your previous question , why not use it then?? [~,~,c]=unique(A,'stable'); B = B(c)

Could anyone help me to solve the issue.

Looks like it's the same as your previous question , why not use it then?? [~,~,c]=unique(A,'stable'); B = B(c)

5 days ago | 0

Answered

could anyone help me to solve the issue

[~,~,c] = unique(B,'stable'); A = A(c)

could anyone help me to solve the issue

[~,~,c] = unique(B,'stable'); A = A(c)

6 days ago | 1

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Answered

how can i add two matrix vertically with different column

m = max(numel(A),numel(B)); % Method 1 Wanted = reshape([A(:);B(:);zeros(m-numel(B),1)],[],2).' % Method 2 w = cellfun(@(x)...

how can i add two matrix vertically with different column

m = max(numel(A),numel(B)); % Method 1 Wanted = reshape([A(:);B(:);zeros(m-numel(B),1)],[],2).' % Method 2 w = cellfun(@(x)...

6 days ago | 1

| accepted