Single Precision Math
This example shows how to perform arithmetic and linear algebra with single precision data. It also shows how the results are computed appropriately in single-precision or double-precision, depending on the input.
Create Double Precision Data
Let's first create some data, which is double precision by default.
Ad = [1 2 0; 2 5 -1; 4 10 -1]
Ad = 3×3
1 2 0
2 5 -1
4 10 -1
Convert to Single Precision
We can convert data to single precision with the single
function.
A = single(Ad); % or A = cast(Ad,'single');
Create Single Precision Zeros and Ones
We can also create single precision zeros and ones with their respective functions.
n = 1000; Z = zeros(n,1,'single'); O = ones(n,1,'single');
Let's look at the variables in the workspace.
whos A Ad O Z n
Name Size Bytes Class Attributes A 3x3 36 single Ad 3x3 72 double O 1000x1 4000 single Z 1000x1 4000 single n 1x1 8 double
We can see that some of the variables are of type single
and that the variable A
(the single precision version of Ad
) takes half the number of bytes of memory to store because singles require just four bytes (32-bits), whereas doubles require 8 bytes (64-bits).
Arithmetic and Linear Algebra
We can perform standard arithmetic and linear algebra on singles.
B = A' % Matrix Transpose
B = 3x3 single matrix
1 2 4
2 5 10
0 -1 -1
whos B
Name Size Bytes Class Attributes B 3x3 36 single
We see the result of this operation, B
, is a single.
C = A * B % Matrix multiplication
C = 3x3 single matrix
5 12 24
12 30 59
24 59 117
C = A .* B % Elementwise arithmetic
C = 3x3 single matrix
1 4 0
4 25 -10
0 -10 1
X = inv(A) % Matrix inverse
X = 3x3 single matrix
5 2 -2
-2 -1 1
0 -2 1
I = inv(A) * A % Confirm result is identity matrix
I = 3x3 single matrix
1 0 0
0 1 0
0 0 1
I = A \ A % Better way to do matrix division than inv
I = 3x3 single matrix
1 0 0
0 1 0
0 0 1
E = eig(A) % Eigenvalues
E = 3x1 single column vector
3.7321
0.2679
1.0000
F = fft(A(:,1)) % FFT
F = 3x1 single column vector
7.0000 + 0.0000i
-2.0000 + 1.7321i
-2.0000 - 1.7321i
S = svd(A) % Singular value decomposition
S = 3x1 single column vector
12.3171
0.5149
0.1577
P = round(poly(A)) % The characteristic polynomial of a matrix
P = 1x4 single row vector
1 -5 5 -1
R = roots(P) % Roots of a polynomial
R = 3x1 single column vector
3.7321
1.0000
0.2679
Q = conv(P,P) % Convolve two vectors
Q = 1x7 single row vector
1 -10 35 -52 35 -10 1
R = conv(P,Q)
R = 1x10 single row vector
1 -15 90 -278 480 -480 278 -90 15 -1
stem(R); % Plot the result
A Program That Works for Either Single or Double Precision
Now let's look at a function to compute enough terms in the Fibonacci sequence so the ratio is less than the correct machine epsilon (eps
) for datatype single or double.
% How many terms needed to get single precision results? fibodemo('single')
ans = 19
% How many terms needed to get double precision results? fibodemo('double')
ans = 41
% Now let's look at the working code. type fibodemo
function nterms = fibodemo(dtype) %FIBODEMO Used by SINGLEMATH demo. % Calculate number of terms in Fibonacci sequence. % Copyright 1984-2014 The MathWorks, Inc. fcurrent = ones(dtype); fnext = fcurrent; goldenMean = (ones(dtype)+sqrt(5))/2; tol = eps(goldenMean); nterms = 2; while abs(fnext/fcurrent - goldenMean) >= tol nterms = nterms + 1; temp = fnext; fnext = fnext + fcurrent; fcurrent = temp; end
Notice that we initialize several of our variables, fcurrent
, fnext
, and goldenMean
, with values that are dependent on the input datatype, and the tolerance tol
depends on that type as well. Single precision requires that we calculate fewer terms than the equivalent double precision calculation.