getClassNamespace

Get class namespace for a model

Since R2021a

Syntax

namespace = getClassNamespace(myCPPMappingObj)

Description

namespace = getClassNamespace(myCPPMappingObj) returns the class namespace specified for the model. Class namespaces can help to prevent name conflicts in large projects.

Examples

Access Class Namespace for Model

Open the model. To access the CodeMappingCPP object associated with the model, use the coder.mapping.api.get function.

open_system('CppClassRateBased');
cm = coder.mapping.api.get('CppClassRateBased');

Use the getClassNamespace function to access the namespace of the model.

If you did not specify a namespace for the model, the getClassNamespace function returns an empty character vector.

name = getClassNamespace(cm)

name = 
'example_ns'

Specify a namespace for the model by using the setClassNamespace function.

setClassNamespace(cm, 'myClassNamespace');

The getClassNamespace function now returns the specified class namespace.

name = getClassNamespace(cm)

name = 
'myClassNamespace'

Input Arguments

myCPPMappingObj — C++ code mapping object

CodeMappingCPP object

C++ code mapping object, returned by a call to either the coder.mapping.utils.create function or the coder.mapping.api.get function.

Output Arguments

namespace — Class namespace of model

character vector

Class namespace of model, returned as a character vector. If you did not specify a namespace for the model, the getClassNamespace function returns an empty character vector.

Version History

Introduced in R2021a