Convert date and time to vector of components

The `datevec`

function creates a
numeric array whose values represent the date and time components
of years, months, days, hours, minutes, and seconds. However, the
best way to represent points in time is by using the `datetime`

data
type. The best way to represent elapsed time is by using the `duration`

or `calendarDuration`

data
types.

`DateVector = datevec(t)`

`DateVector = datevec(DateNumber)`

`DateVector = datevec(DateString)`

`DateVector = datevec(DateString,formatIn)`

`DateVector = datevec(DateString,PivotYear)`

`DateVector = datevec(DateString,formatIn,PivotYear)`

`[Y,M,D,H,MN,S] = datevec(___)`

converts the datetime or duration values in the input array `DateVector`

= datevec(`t`

)`t`

to date vectors. The `datevec`

function returns an
`m`

-by-6 matrix where each row corresponds to a value in
`t`

.

converts one or more date numbers to date vectors. The
`DateVector`

= datevec(`DateNumber`

)`datevec`

function returns an `m`

-by-6
matrix containing `m`

date vectors, where `m`

is the total number of date numbers in `DateNumber`

.

converts text representing dates and times to date vectors. If the format used
in the text is known, specify the format as `DateVector`

= datevec(`DateString`

)`formatIn`

.
Syntaxes without `formatIn`

are significantly slower than
syntaxes that include it.

uses `DateVector`

= datevec(`DateString`

,`formatIn`

)`formatIn`

to interpret the dates and times
represented by `DateString`

.

uses `DateVector`

= datevec(`DateString`

,`PivotYear`

)`PivotYear`

to interpret text that specifies the year as
two characters. If the format used in the text is known, specify the format as
`formatIn`

. Syntaxes without `formatIn`

are significantly slower than syntaxes that include it.

uses `DateVector`

= datevec(`DateString`

,`formatIn`

,`PivotYear`

)`formatIn`

to
interpret the dates and times represented by `DateString`

,
and `PivotYear`

to interpret text that specifies
the year as two characters. You can specify `formatIn`

and `PivotYear`

in
either order.

returns
the components of the date vector as individual variables `[Y,M,D,H,MN,S]`

= datevec(___)`Y`

,
`M`

, `D`

, `H`

,
`MN`

, and `S`

(year, month, day, hour,
minutes, and seconds). The `datevec`

function returns
milliseconds as a fractional part of the seconds (`S`

)
output.

When computing date vectors,

`datevec`

sets month values less than 1 to 1. Day values,`D`

, less than 1 are set to the last day of the previous month minus |`D`

|. However, if 0 ≤`DateNumber`

< 1, then`datevec(DateNumber)`

returns a date vector of the form`[0 0 0 H MN S]`

, where`H`

,`MN`

, and`S`

are hours, minutes, and seconds, respectively.

The vectorized calling syntax can offer significant performance improvement for large arrays.