How to use for loop to get the minimum number in an array
4 views (last 30 days)
Show older comments
For simplicity, I have
A=[ 11 7 10 9 6 4 3]
and
B=8
I want to have a for loop to compare each of the elements in A with the latest minimum number from the for loop to get the final minimum number in A.
For example, when A(1) compare with B, min=8, then i continue with the A(2) compare with min=8, this time min=7. After that, A(3) compare with min=7, new min=7. The steps continue till the last elements of A.
0 Comments
Accepted Answer
Jos (10584)
on 16 Jun 2014
A = [ 11 7 10 9 6 4 3]
B = 8
result = min([A B])
% or if you insist on using a for-loop (why?)
result = B
for k = 1:numel(A)
if A(k) < result,
result = A(k)
end
end
0 Comments
More Answers (1)
Abhishek M
on 16 Jun 2014
Edited: Abhishek M
on 16 Jun 2014
Hi Grace, I guess this is what you are expecting. Please find the demo example below.
a=[1:2:10];
b=4;
for i=1:5
if a(i)<b
min=b;
else
min=a(i);
end
end
0 Comments
See Also
Categories
Find more on Creating and Concatenating Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!