Help me generating this series of number.

White flag.
I'm trying to make a series of number like below:
1
2
5
10
20
50
100
200
500
...
...
...
1000000000
2000000000
5000000000
but i need a for-end command first
for i=1:20
because i want to use that "20" in other procedure. And the generated numbers willl also be input in another procedure which requires them to be real positive integer.
could you help me?

 Accepted Answer

without loop for
reshape(cumprod([1 2 5;10*ones(9,3)])',[],1);
with loop for
P = zeros(30,1);
for ii = 1:20
if rem(ii,2) == 0,
P(3*(ii/2)-2+(0:2)) = [1;2;5]*10^(ii/2-1);
end
end

3 Comments

Slightly faster alternatives:
reshape(bsxfun(@times,[1; 2; 5], 10.^(0:9)),[],1);
reshape([1; 2; 5] * 10.^(0:9),[],1);
May I ask?
why do you use
P(3*(ii/2)-2+(0:2))= ...
instead of
P(ii)= ...
?
Because, it is necessary to fulfill your two conditions: length (P) = 30, i = 1:20

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More Answers (1)

Thanks dude for a lot of help... I really need this...
Could I ask you for another problem I might have in the future? Thanks

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