Why does start up require internet access?
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I recently upgraded from 2009a to 2012a on Windows XP. 2012a start up takes 3-4 times as long as 2009a start up. However, if I disable my internet connection, they take about the same amount of time to start up. Wireshark (network analyzer) confirms that 2012a repeatedly tries to connect to various servers, while 2009a does no such thing. Why does 2012a need the internet to start up? How can this behavior be eliminated or sped up? Thanks for any help you can give.
4 Comments
Walter Roberson
on 4 Nov 2013
The servers that it attempts to contact: are you blocking them with a firewall, or is it not able to contact them, or is it trying different servers on different runs? Is there a DNS lookup taking place before the contact? If so then snooping the lookup might give you information about what is being accessed.
Andy Yancy
on 4 Nov 2013
Edited: Andy Yancy
on 4 Nov 2013
Andy Yancy
on 6 Nov 2013
Image Analyst
on 6 Nov 2013
You mean the Mathworks couldn't answer your question when you called them today?
Answers (2)
Dear Andy, maybe following links are helpful for you:
I hope it helps. Good luck!
2 Comments
Image Analyst
on 4 Nov 2013
None of these say that a personal stand-alone license should access the network. The third link say that network access may be attempted if they have a shared/network license, but Andy says he does not have that kind of license.
Andy Yancy
on 4 Nov 2013
Edited: Andy Yancy
on 4 Nov 2013
Image Analyst
on 4 Nov 2013
0 votes
Maybe you have a shared license that you have to check out from a central server? Or do you have a personal non-shared license?
4 Comments
Andy Yancy
on 4 Nov 2013
Image Analyst
on 4 Nov 2013
What happens if it is enabled? What abnormal things happen when you start MATLAB then?
What does enabled mean? Like you have an internet connection? And how do you disable it to get it to work normally ? Unplug the cable and turn off your wireless adapter? Or some other way?
Andy Yancy
on 4 Nov 2013
Edited: Andy Yancy
on 4 Nov 2013
Image Analyst
on 4 Nov 2013
I think you'll have to ask the Mathworks. All we can do is guess, which is not definitive.
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