need to remove [] in cell

I have once cell Z ={1x3 cell} [] {1x2 cell} [] {1x4 cell}

and then i have once cell Z = {1x7 cell} {1x5 cell} , Z{1}= [] [1x3 double] [] [1x3 double] [] [1x3 double] [1x3 double]

i find loop,if i have Z={1x3 cell} [] {1x2 cell} [] {1x4 cell} []; will be used Z(cellfun('isempty',Z))=[]; and then in 2 iteration is at the position Z{1}=[]; was be used: i=1:size(Z,2) Z{i}(cellfun(@isempty,Z{i})) = []; end

I want to write in one loop.

I have a dual results, I have once Z={1x3 cell} [] {1x2 cell} [] and once i have a results Z={1x3cell},in cell Z{1}=[] {1x2cell} I need to remove blanks place in cell i find one loop,in which I can use my cood

for example my cood

for i=size(Z,2)

    if length(Z{i})==0

         Z(cellfun('isempty',Z))=[];

   Z

    else

         for i=1:size(Z,2) %
          Z{i}(cellfun(@isempty,Z{i})) = [];
      end
      Z

end end

cod reports an error

??? Error using ==> cellfun Input #2 expected to be a cell array, was double instead.

Thanks.

[dpb]

I can't parse the actual request, sorry...perhaps give an example of what output you expect as well would help. Is it you're trying to simply process Z skipping over the empty cells or is it adequate to reduce Z by removing empty cells entirely?

As for the error,

           Z{i}(cellfun(@isempty,Z{i})) = [];
??? Error using ==> cellfun Input #2 expected to be a cell array, was double instead.

The problem here is you dereferenced Z(i) by using the curlies {} so the result of Z{} is the array not the cell.