# Remake this without a loop

2 views (last 30 days)
sznailc on 17 Oct 2021
Edited: DGM on 17 Oct 2021
How to rewrite this without using a loop?
Basically I want to replace elements in matrix A with 0, that are equal to any of element in vector "vector"
vector = [A(A >= 1.5)].' % Vector, don't change.
for i = 1:vector
A(A == vector(i)) = 0;
end

the cyclist on 17 Oct 2021
% Pretend data
A = 1 : 7;
vector = [2 3 5];
% Replace values of A with 0, if they are in vector
A(ismember(A,vector)) = 0
A = 1×7
1 0 0 4 0 6 7

DGM on 17 Oct 2021
Edited: DGM on 17 Oct 2021
What's wrong with just using the test you're already doing? In the case you've given, the vector is unnecessary.
A(A >= 1.5) = 0;
Or more generally, if you actually need to test against another set,
A = randi(5,5,8)
v = [3 4];
A(ismember(A,v)) = 0;

### Categories

Find more on Logical in Help Center and File Exchange

R2021a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!