Help creating loop that converts text to numbers

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Alex Skantz
Alex Skantz on 22 Oct 2021
Edited: dpb on 23 Oct 2021
Hi, this is a follow-up on a question I asked yesterday.
I have a loop that asks the user to input sentences until the word 'end' is typed.
After the loop has ended, I want it to display the sentences typed as inegers, using the "char" command
char([101 102 103])
but reversed since it would be taking the letters and converting them to integers.
Here is what I have so far.
The other loop to execute this specific function is probably extremely wrong but I am an absolute beginner and was just trying to follow a similar format to the first loop I recieved some help with yesterday.
N=input('what is N?: ') %establishes N
all_A = {};
while true
A = input('give me a sentence!: ','s'); %asks user for sentence input
if strcmpi(strtrim(A), 'end');
end %will end the loop if end is typed
all_A{end+1} = A;
while false
B= input('give me a sentence!: ','s');
if strcmpi(strtrim(B));

Answers (1)

dpb on 22 Oct 2021
>> A='Now is the time...';
>> format short
>> disp(double(A))
78 111 119 32 105 115 32 116 104 101 32 116 105 109 101 46 46 46
>> char(double(A))
ans =
'Now is the time...'
The converse of char() is simply one of the numeric classes; by default everything numeric in MATLAB is double so I used it. Could just as well have used
>> int8(A)
ans =
1×18 int8 row vector
78 111 119 32 105 115 32 116 104 101 32 116 105 109 101 46 46 46
dpb on 23 Oct 2021
As noted, UNTESTED code...I had never tried double on a string; I presumed it would behave as expected; turns out it doesn't. A string variable is higher abstraction and contains a cellstr() underneath, but to convert to underlying numeric turns out you have to explicitly address that content -- "Use the curlies, Luke!"

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