how can remove the object that has the maximum distance from center of image?
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Edited: Matt J on 17 Oct 2014
how can I obtain this image as result:
I don't recommend that you use distance as a criterion. It would work, but for the object you've shown, it seems quicker and easier to use solidity,
This is also shift-invariant, whereas the distance criterion is not.
Image Analyst on 17 Oct 2014
sara: Try the attached code (below the image in blue). I basically threshold, do a morphological opening to break away the thin table line, then extract the biggest blob. A snippet:
% Get the binaryImage
binaryImage = grayImage > 135;
% Erode to break away the table from the body
binaryImage = imopen(binaryImage, [1;1;1]);
biggestBlob = ExtractNLargestBlobs(binaryImage, numberToExtract);
It gives the image below:
Image Analyst on 22 Jan 2015
Sara, regarding your comment about finding the closest pair of blobs...
"Close" has several definitions. See Hausdorf distance. But let's just assume you want the pair that has the lowest distance between the centroids. Just get the centroids using regionprops() into two arrays centroidx and centroidy. Then calculate the distances, something like
distances = zeros(numberOfBlobs, numberOfBlobs);
for b1 = 1 : numberOfBlobs
for b2 = b1 : numberOfBlobs
distances(b1,b2) = sqrt((centroidx(b1)-centroidx(b2))^2+(centroidy(b1)-centroid(b2))^2);
Then find the min pair
[blob1, blob2] = find(distances == min(distances(:)));
Then use ismember() to extract those two blobs:
binaryImage = ismember(labeledImage, [blob1, blob2]) > 0;
or something like that. That's just off the top of my head and may need editing.
If this answers your question, can you "Accept" my answer?