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Sorting numbers randomly in a specified range without changing their positions

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A = [5 8 8 4 0 0 10 10 2 2];
Since A is in the range of 1:10, I want to sort A such that all the repeated numbers are replaced with numbers that hasn't appeared yet within 1 to 10, slotting those numbers in, randomly, without ascending or descending. All their initial positions should be maintained without changing. All zeros will also be replaced with non-zeros in this specified range. Maybe to get a result like below.
Ans = [5 8 1 4 7 3 10 6 9 2];

Accepted Answer

the cyclist
the cyclist on 26 Nov 2021
% Input
A = [5 8 8 4 0 0 10 10 2 2];
% Find the pool of numbers that are available to fill
% (because they don't appear in A, but are in 1:10, in this case)
pool = setdiff(1:numel(A),unique(A));
% Find the locations to place the numbers
% (i.e. repeats and zeros)
loc = (diff([NaN A]) == 0) | (A==0);
% Fill the locations randomly from the pool
A(loc) = pool(randperm(numel(pool)))
A = 1×10
5 8 7 4 1 6 10 9 2 3
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