Divide a scalar by all non-zero values in a matrix row and input results into a new matrix
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I have a matrix cA. I want to input values into a matrix A that are a scalar (1E-14) divided by each element in a row of cA that is not equal to zero.
I have so far:
A = (1E-14)./cA(i,:);
but this uses every column in the ith row. Some of the cell values in the columns are zero so the result is infinity in some cells/elements of A. I would only like to input a value into an element of A if cA(i,j) > 0. Alternatively, if the result is infinity, then just input a zero into that element of A.
4 Comments
Meg Noah
on 3 Jan 2022
Another Trick:
verySmallNumber = 1.0e-32;
denom = cA;
denom(abs(denom) < verySmallNumber & denom > 0) = verySmallNumber;
denom(abs(denom) < verySmallNumber & denom < 0) = -verySmallNumber;
A=MAGICCONSTANT./denom;
dpb
on 3 Jan 2022
OBTW,
A(isinf(A)) = 0;
also works by definition that
isinf(-inf) == isinf(+inf)
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