- using a loop
- replicating B in the third dimension to match the size of A
Change array elements that meet a condition - Multidimensional array case
2 views (last 30 days)
Show older comments
I can handle this in the case of two-dimensional arrays.
I have trouble in the case of multidimensional arrays. For example
A=ones(4,4,2);
B=zeros(4); B(2:4,2:4)=3;
I would like to change the value of all elements on each page of A this way
A=reshape(A,16,2);
B= reshape(B,16,1);
A(B==3,:)=0;
A=reshape(A, 4, 4, 2)
Is it possible to obtain that result without reshapes?
In general, how to handle conditions that apply only to some indexes in multidimensional arrays?
PS: A and B are very large data matrices.
0 Comments
Answers (1)
Rik
on 21 Jan 2022
I can think of two ways:
I suspect the first way would be faster, but I think that might depend on the sizes of the array and the physical memory.
2 Comments
Rik
on 21 Jan 2022
A for loop may actually be very efficient, unless the third dimension is large relative to the product of the other two. I don't think the reshape calls are that cheap in the end.
The only way to know for sure is to test it.
See Also
Categories
Find more on Resizing and Reshaping Matrices in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!