How to split binary cells and convert them to dec?
1 view (last 30 days)
Show older comments
I have a cell array consisting of binary 100x1 e.g
{'0100101000101000'}
{'0100101000101000'}
{'0100101000101000'}
...
{'0100101000101000'}
How do i take the first 3 binary from each cell and then convert it into dec?
maybe a cellfun can be helpful here but i do get some errors
I know you can use bin2dec i should expect a 2 for every cell.
Thanks!
0 Comments
Accepted Answer
zhehao.nkd
on 25 Jan 2022
C{1} = {'0100101000101000'};
C{2} = {'0100101000101000'};
C{3} = {'0100101000101000'};
if C is your original cell, then:
cellfun(@(x) bin2dec(x{1}(1:3)),C)
Is that what you need?
More Answers (1)
Stephen23
on 25 Jan 2022
More efficient than using CELLFUN:
C = {'0100101000101000';'0100101000101000';'0100101000101000';'0100101000101000'}
V = [4,2,1]*sscanf(sprintf('%s ',C{:}),'%1d%1d%1d%*d',[3,Inf])
0 Comments
See Also
Categories
Find more on Matrices and Arrays in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!