Convolution theorem. Fourier transform.

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Dimani4
Dimani4 on 6 Dec 2014
Commented: Matt J on 7 Dec 2014
Hey ppl,
I have a question about convolution and Fourier transform. I have Final picture and initial picture. I know that the final picture results as convolution between the initial and something else, i.e. final picture=initial picture(*)X. All we know that F{final picture}=F{initial picture}F{X}=>F{X}=F{final picture}/F{initial picture}; then X=F{X}^(-1). Pretty easy but I got a blank picture after that manipulations. Take a look part of my code:
FFT_picture=fft2(picture); %?
FFT_hole=fft2(hole); %?
FFT_X=FFT_picture./FFT_hole;
X=ifft2(FFT_X);
what I do wrong?
I've attached two files. The first one is the initial picture and the second one is the final picture.
Thank you.
  1 Comment
Matt J
Matt J on 6 Dec 2014
I've attached two files. The first one is the initial picture and the second one is the final picture.
If you attach "picture" and "hole" in a .mat file instead, it will be easier for people to repeat your test.

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Answers (1)

Matt J
Matt J on 6 Dec 2014
Edited: Matt J on 6 Dec 2014
Your procedure won't work if FFT_hole has some pixels containing zero (or nearly zero). If that happens then your calculation of FFT_X will have a divide-by-zero situation and give NaNs and/or Infs in those pixels. Passing that through ifft2() will just yield junk.
You might want to look at deconvreg() instead.
  2 Comments
Dimani4
Dimani4 on 7 Dec 2014
No. It doesnt work. It gave me just a number. Secondly this function doesnt work with matrices, only with vectors. So I reshape it to vectors and added some numbers instead zeros. My pictures contain zeros. I wonder is any body didnt encounter with such a problem.
Matt J
Matt J on 7 Dec 2014
You're using it wrong somehow. It's an Image Processing Toolbox function. It's specifically meant for image deconvolution. There is an example in its documentation.

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