Assign a colormap to an array to plot with the nsidepoly function.

Hi, this code plots a hexagonal mesh using the nsidedpoly function, where each hexagon is labeled with the corresponding r-value. The problem is that each hexagon is plotted independently and I can't apply any colormap only the red color (FaceColor.) How can I assign the values of a colormap (for example jet()) to the r-values depending on their value?

Thanks in advance.

x = load('COORDXY');
coord = [x(230:235, :)
		x(256:262, :)
		x(282:289, :)
		x([308:310,312:316], :)
		x(334:343, :)
		x([360:364,366,368:370], :)
		x(387:396, :)
		x([414:416,418:422], :)
		x(441:448, :)
		x(468:474, :)
		x(495:500, :)];

for i = 1:length(coord)	
	poly(i) = nsidedpoly(6, 'Center', coord(i, :), 'SideLength', 5.6617);
end

pg = plot(poly);
axis off
axis equal

a = 0.5;
b = 1.5;
r = (b-a).*rand(87, 1) + a;

cmap = jet(15);
colormap(jet(10));

for i = 1:length(pg)
	pg(i).FaceColor = 'r';
end

colormap(jet(10));
cmap = jet(87);

str = num2str(r, 2);
t2 = text(coord(:, 1), coord(:, 2), str, ...
    'HorizontalAlignment', 'center','VerticalAlignment','middle', 'FontSize', 10, 'FontName', 'Times');

Answer 1

[Simon Chan]

You may try the following:

clear; clc;
coord = [1 1;4 4;7 7;10 10];
a = 0.5;
b = 1.5;
r = (b-a).*rand(4, 1) + a;
nLevel = 100;                                               % Number of level in the colormap
cmap = colormap(jet(nLevel));                               % Select your colormap
polyFaceColor = cmap(ceil((r-a)*nLevel),:);                 % Calculate which level of the colormap for each polygon
for i = 1:length(coord)	
	pgon(i) = nsidedpoly(6, 'Center', coord(i, :), 'SideLength', 2);
end
pg = plot(pgon);
axis off
axis equal
for i = 1:length(coord)	
    pg(i).FaceColor = polyFaceColor(i,:);                   % Assign the colormap to the polygon
end
str = num2str(r, 2);
t2 = text(coord(:, 1), coord(:, 2), str, ...
    'HorizontalAlignment', 'center','VerticalAlignment','middle', 'FontSize', 10, 'FontName', 'Times');

[Yro]

It works perfectly, thank you very much.