exportgraphics dynamic file name

7 views (last 30 days)
Pelajar UM
Pelajar UM on 22 Mar 2022
Commented: Ive J on 22 Mar 2022
What's the correct syntax if you want to name the files dynamically when using exportgraphics?
I have a cell array A with 16 titles in each columns that are assigned to the colorbar string. I want to use the same titles to name the files.
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = string (A (:,k));
exportgraphics(gcf, string (A(:,k)) '.png' ,'Resolution',DPI) %this doesn't work
end

Accepted Answer

Ive J
Ive J on 22 Mar 2022
% A = {'name1', ...}
for k = 1:16
%rest of the code
c = colorbar;
c.Label.String = A{k};
exportgraphics(gcf, string(A{k}) + ".png" ,'Resolution',DPI) %this doesn't work
end
You could also use strcat, join or similar functions.
  10 Comments
Ive J
Ive J on 22 Mar 2022
Glad it works
cheers!

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!