How can I get the full path of my current *.mlapp file?

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I'm building a gui via App Designer. I'd like to specify a path of an XML file. I'd like it to be relative to my main *.mlapp file.
Eventually, I'd like to ha ve a general function of the following format:
IF running in StandAlone Mode --> XML file path should be relative to where the exe file recides (when distributed, I'd ask the users to keep this XML file in the same folder as the exe file).
IF running in Developers Mode --> XML file path should be relative to when the *.mlapp file recides.

Accepted Answer

Mark Golberg
Mark Golberg on 19 Jun 2022
if isdeployed
% User is running an executable in standalone mode.
[~ , result] = system('set PATH');
executableFolder = char(regexpi(result, 'Path=(.*?);', 'tokens', 'once'));
% User is running an m-file from the MATLAB integrated development environment (regular MATLAB).
tmp_path = mfilename('fullpath');
[executableFolder , ~ , ~] = fileparts(tmp_path);
  1 Comment
Mark Golberg
Mark Golberg on 19 Jun 2022
I use the above code in a function, and then the function m-file location in the same folder as the *.mlapp file.

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More Answers (1)

Fangjun Jiang
Fangjun Jiang on 16 Jun 2022
I think you can implement this in your code.
Search for the .exe file or .mlapp file using exist('', 'file'), use which() and fileparts() to get the root directory. If both exists, pick your priority.
Then, use fullfile() to combine the root directory and folder to specify the full path of the .xml file.


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