how to do the matrix value comparison of two different iterations ?

fun [ …… …. ]= mainfun [………………….]
iteration=1
while iteration<maxiterationno
some parameter and their calculation
[ ]=subfun1 [];
[ ,out2 ]=subfun2[];
Newoutput=out2(1:10,:)
Iteration=iteration+1;
end
maybe from subfun2 I will get one output called out2 ,I want to do the comparison of iteration number i and iteration i+1 ,if iteration i+1 give me better solution like the summation of any specific column value is greater than the ith iteration then my iteration should be stop and it will show me the best solution value .

 Accepted Answer

yes, you can do this like you say by saving the best result and updating it at each iteration
i tried to update the pseudo code to give you the idea
function [] = mainfun()
iteration = 0;
old_out2 = 0;
c = 2; % column to check
while iteration < max_iteration
% increase the counter
iteration = iteration + 1;
% some parameter and their calculation
[] = subfun1();
[, out2] = subfun2();
if iteration == 1
% at the first iteration save the result
old_out2 = out2;
else
% for all other iterations, check if the new result is bigger
if sum( old_out2(:,c) ) < sum( out2(:,c) )
% if so break the loop
break
end
end
end

4 Comments

Thank you so much .It's a great help .Can you tell me how to see the exact iteration number where the loop is breaking ?
this will automatically be stored in the variable 'iteration', this is why i placed the 'break' at the end of the loop.
I have a question ,maybe after certain iteration number i got my expected result but if i want to do another 3 to 5 iteration more and if i get everytime better solution then i want to stop the iteration .Then how to implement inside the code ?

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Asked:

on 22 Jun 2022

Commented:

on 4 Nov 2022

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