matrix array
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Please can someone be of help? Here is my code below:
a=[2 2 2 2 4 4 4 4];
b = [0 0 0 0 1 1 1 1];
c = Shuffle(b);
d = c(a)
When I finished inputting the code, d returned 8 zeros. Instead I want after randomizing c, then d will return two (zeros) and two(ones) that tally with the four (2's) and four (4's)in the first variable a. In other words,I want d to return two zeros and two ones for the 2's and the same also for the 4's regardless of the order. In essence I want d to return something like this: d = 0 1 0 1 1 0 0 1 OR 0 0 1 1 0 1 1 0. Thanks in advance, Tom.
2 Comments
Answers (2)
the cyclist
on 4 Oct 2011
I don't really understand what you want. But I think you can probably make good use of the randperm() command.
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Fangjun Jiang
on 4 Oct 2011
Okay, shuffle() is your own function. I can do that using randperm() like cyclist suggested. It's basically the same.
a=[2 2 2 2 4 4 4 4];
b = [0 0 0 0 1 1 1 1];
c = b(randperm(length(b)));
d = c(a)
Since a is [2 2 2 2 4 4 4 4], so d will be the 2nd and 4th value of c, each repeats 4 times. So d has 4 possible answer.
- all zeros
- all ones
- four zeros and then four ones
- four ones and then four zeros
Please double check your logic to see if you missed anything.
Considering your expected output, maybe all you need is:
d=b(randperm(length(b)))
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