# Replace values in a matrice

2 views (last 30 days)
Miguel Albuquerque on 17 Jul 2022
Edited: Miguel Albuquerque on 19 Jul 2022
I have this range(matrix) that has 1 x 5600 values. After that I perform a calculation , and I get a distance_matrix, that has 1 x 400 values.
Range includes the values in distance_matrix
What I want to do, is find in range the indexes where the values of distance_matrix are, and replace them by RMC, but such as, range continues to have 1 x 5600 values.
How can I do that?

dpb on 17 Jul 2022
Edited: dpb on 17 Jul 2022
Seems you're going over and over the same plowed ground here...use logical addressing.
isR=isfinite(D);
R(isR)=RMC;
or
isD=ismember(R,D);
R(isD)=RMC;
dpb on 19 Jul 2022
Well, that doesn't match the computed values or you wouldn't have the mismatch in lengths...
The code put a NaN or Inf out of range and 0 at the origin; the calculation of whatever was over the values in range which are the finite elements -- makes no sense otherwise.
Miguel Albuquerque on 19 Jul 2022
Edited: Miguel Albuquerque on 19 Jul 2022
Look this is the way I managed to do, is not fully automatized, but It works for waht I want, i just sometimes need to replace the last line of code, Is there a way I could do this in a more automatic way?
isR=find(y_max);
y_cutted=y_max(isR);
[a,b]=intersect(range,y_cutted);
b=b.';
RMC2=RMC(:,184:255);
range(:,(254:325))=RMC2;

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